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elixir [45]
3 years ago
14

Graph y > x2 - 3. Click on the graph until the correct graph appears.

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
6 0

Answer:(0/7) and (2/5)

Step-by-step explanation:

I did the test

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Factor completely. 5x^2-20x+20=5x 2 −20x+20
Harman [31]

Step-by-step explanation:

5x^2 - 20x + 20 = 5x^2 - 20x + 20

5(x^2 - 4x + 4) = 5(x^2 - 4x + 4)

(5 + 5) (x^2 - 4x + 4)

5 0
3 years ago
Use the following compound interest formula to complete the problem. a = p (1 startfraction r over n endfraction) superscript n
Ratling [72]

The final amount that Victor will owe after one year, to the nearest cent is given by: Option C: $545.65

<h3>How to find the compound interest?</h3>

If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:

a = p(1 + \dfrac{r}{n})^{nt}

For this case, we're provided that:

The interest rate is r = 13.66% = 13.66/100 = 0.1366 (converted percent to decimal)

It is compounding monthly, thus, 12 times a year, or n = 12

The initial amount that the credit card of Victor has = p = $1349.34

Time for which interest was compounded = a year = 1 = t

Thus, the final amount that Victor will owe after one year to the nearest cent is calculated as;

a = p(1 + \dfrac{r}{n})^{nt}\\\\a = 1349.34(1 + \dfrac{0.1366}{12})^{12\times 1}\\\\a = 1349.34(1.01138)^{12} \approx 1245.65 \: \rm (in \: dollars)

Thus, the final amount that Victor will owe after one year, to the nearest cent is given by: Option C: $545.65

Learn more about compound interest here:

brainly.com/question/1329401

4 0
3 years ago
What i the scientific notation of 13400000<br> correct answer only
olasank [31]

Answer:

1.34 x 10^7

Step-by-step explanation:

I hope this helped!

4 0
3 years ago
23+8-(14-(7-2+3) step by step
Snowcat [4.5K]

Step 1: Do the most inner parenthesis (7-2+3) = 5 + 3 = 8.

23+8-(14-8)

Step 2: Do the next parenthesis (14-8) = 6

23+8-6

23+8 = 31

31 - 6 = 25

So, 25 is your answer!

7 0
3 years ago
Each year about 1500 students take the introductory statistics course at a large university. This year scores on the nal exam ar
nikitadnepr [17]

Answer:

a) Left-skewed

b) We should expect most students to have scored above 70.

c) The scores are skewed, so we cannot calculate any probability for a single student.

d) 0.08% probability that the average score for a random sample of 40 students is above 75

e) If the sample size is cut in half, the standard error of the mean would increase fro 1.58 to 2.24.

Step-by-step explanation:

To solve this question, we need to understand skewness,the normal probability distribution and the central limit theorem.

Skewness:

To undertand skewness, it is important to understand the concept of the median.

The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.

If the median is larger than the mean, the distribution is left-skewed.

If the mean is larger than the median, the distribution is right skewed.

Normal probabilty distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation, also called standard error of the mean s = \frac{\sigma}{\sqrt{n}}

(a) Is the distribution of scores on this nal exam symmetric, right skewed, or left skewed?

Mean = 70, median = 74. So the distribution is left-skewed.

(b) Would you expect most students to have scored above or below 70 points?

70 is below the median, which is 74.

50% score above the median, and 50% below. So 50% score above 74.

This means that we should expect most students to have scored above 70.

(c) Can we calculate the probability that a randomly chosen student scored above 75 using the normal distribution?

The scores are skewed, so we cannot calculate any probability for a single student.

(d) What is the probability that the average score for a random sample of 40 students is above 75?

Now we can apply the central limit theorem.

\mu = 70, \sigma = 10, n = 40, s = \frac{10}{\sqrt{40}} = 1.58

This probability is 1 subtracted by the pvalue of Z when X = 75. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{75 - 70}{1.58}

Z = 3.16

Z = 3.16 has a pvalue of 0.9992

1 - 0.9992 = 0.0008

0.08% probability that the average score for a random sample of 40 students is above 75

(e) How would cutting the sample size in half aect the standard error of the mean?

n = 40

s =  \frac{10}{\sqrt{40}} = 1.58

n = 20

s =  \frac{10}{\sqrt{20}} = 2.24

If the sample size is cut in half, the standard error of the mean would increase fro 1.58 to 2.24.

4 0
3 years ago
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