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3 years ago

HELP FOR 20 POINTSSS

Mathematics

1 answer:

Monica [59]3 years ago

4 0

Answer:

The first one.

Step-by-step explanation:

solving for x:

5/2 = 7.5/x

cross multiply

2 ×7.5 =5x

x= 2×7.5/5

x= 3

solving for y:

values of the small triangle over the bigger triangle-

5/6 =7/y

cross multiply and solve for y

y= 8.4

therefore (x= 3; y= 8.4)

YOU ARE VERY WELCOME!

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klemol [59]

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3 years ago

The sum of two consecutive odd numbers is 284

kiruha [24]

141 and 143 adds to 248

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3 years ago

In a school auditorium, the number of chairs in a row is the same as the number of rows of chairs. There are 7033 students in th

mafiozo [28]

Same number of rows to chairs in a row would form a square.

Use the total number of students as the area

Find the number or rows by taking the square root of student:

The square root of 7033 is 83.86

Round up to 84

Total seats would be rows x seats per row:

84 x 84 = 7,056 total seats

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3 0

3 years ago

Substitution method need help for home work

Marizza181 [45]

-3y = x...so we sub in -3y for x in the other equation

-x + 7y = 70
-(-3y) + 7y = 70
3y + 7y = 70
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y = 7

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6 0

3 years ago

Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int

meriva

Answer:

b) 95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14

sample standard deviation 'S' = 9.3

95 percent confidence interval for this single-sample t test

The values are $(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })$ the 95 percent confidence interval for the population mean 'μ'

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

$(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })$

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

Conclusion:-

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

6 0

3 years ago