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puteri [66]
3 years ago
7

We are taking a survey with kids from different grades on which movie genre they prefer best. There are 4 ninth graders and 3 of

them do not prefer action but one does. What is the probabilty that a student does not prefer action, given that the student is in 9th grade?
Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0
It depends on how many kids are in the other grades
Rzqust [24]3 years ago
8 0
If there are 4 ninth graders total, and 3 of them don’t like action, the probability of a randomly selected ninth grader not preferring action is 3/4.
If there are more than 4 ninth graders total - the survey suggests that approximately 3/4 ninth graders do not prefer action. We can then approximate the probability that a randomly selected ninth grader does not prefer action as 3/4.
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I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr
Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0
4 years ago
Read 2 more answers
Can u tell me the answer?
vovikov84 [41]
I cannot do that unfortunately
3 0
3 years ago
−110=13+3(4h−6) i need to know the answer for h can someone help
Pepsi [2]

13+3(4h-6)=-110\ \ \ \ |-13\\\\3(4h-6)=-123\ \ \ \ |\text{use the distributive property}\\\\(3)(4h)-(3)(6)=-123\\\\12h-18=-123\ \ \ \ |+18\\\\12h=-105\ \ \ \ |:12\\\\h=-\dfrac{105}{12}\\\\h=-\dfrac{105:3}{12:3}\\\\h=-\dfrac{35}{4}

8 0
3 years ago
PLEASE HELP! Probability!
wlad13 [49]
2+3=5 no
2+5=7 no
2+8=10 yes (if zero counts as an even number)
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5+8=13 no
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6 0
3 years ago
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Could I plz plz have help with factorising this quadratics(not using quadratic formula)
spin [16.1K]

(x-3)^2=(3x+10)*(x-3) so to solve this u can simply take (x-3) over to the other side so it will; look like this

(x-3)^2/(x-3)=3x+10

then it will be x-3=3x+10

-2x=13

x=-13/2 which is -6.5


7 0
4 years ago
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