The coordinates of prs are p(-3,2), R (2,5), s (0,0) which of the following could be p'r's' after a 270 degree rotation

A farmer wants to fence in a rectangular field that encloses 3600 square feet. One side of the field is along a river and does n

andriy [413]

Answer:

C(x) = $\$3.50(\frac{x^2+7200}{x})$

Step-by-step explanation:

Data provided in the question:

Area of the field = 3600 square feet

Fencing charges = $3.50 per foot

Let the side along the river be 'x' feet and the other side of the 'B'

now,

Area of rectangle = Bx = 3600 square feet

or

B = $\frac{3600}{x}$ feet

and total length to be fenced = x + 2B

therefore,

Total cost of fencing = Fencing charges × total length to be fenced

or

Total cost of fencing = $3.50 × ( x + 2B )

substituting the value of B from (1)

Total cost of fencing, C(x) = $\$3.50(x+2\times\frac{3600}{x})$

or

C(x) = $\$3.50(\frac{x^2+7200}{x})$

4 0

3 years ago

One airplane located 200km north and 50km east of an airport. A second plane at the same altitude is located 30km north and 100k

grigory [225]

Answer: 350

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A vendor converts the weights on the packages she sends out from pounds to kilograms (1kg approximately equals 2.2 pounds).

Alexxx [7]

Answer:

a) b) the standard deviation and the mean is affected by the conversion factor as well

c) the mean is displaced by b units

Step-by-step explanation:

for a new variable

Y=a*X , where a= constant (conversion factor= 1 kg/2.2 pounds)

then

p(y)= p(a*X) = p(X)

a) mean =μ=E(Y)= ∑ a*X*p(y) = a ∑ X*p(x) = a* E(X)

mean =μ=a*μₓ

b) σ² = ∑ (Y-μ)²* p(y) = ∑ (a*X-a μₓ)²* p(y) = a²*∑ (X-μₓ)²* p(x) = a²*σₓ²

then

standard deviation = σ= √σ²=√(a²*σₓ²) = a*σₓ

standard deviation = σ= a*σₓ

then the standard deviation and the mean is affected by the conversion factor as well

c) nevertheless for a displacement b

Y₂=X + b (b= constant= 50 gr)

p(Y₂)= p(X + b) = p(X)

then

mean =μ=∑ (X-b)*p(y)=∑ X*p(x)- b ∑ p(x) = E(X) -

mean =μ=μₓ - b

then the mean is displaced by b units

7 0

3 years ago

15X^2+20x factor greatest common monomial

velikii [3]

Both 15 and 20 can be divided evenly by 5, so 5 is the greatest common monomial: 5(3x^2 + 4x) or 5x(3x + 4)

4 0

3 years ago

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among

jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\\=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0

3 years ago