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serious [3.7K]
2 years ago
5

A set of equations is given below: Equation E: m = 4n + 1 Equation F: m = 6n + 8 Which statement describes a step that can be us

ed to find the solution to the set of equations?
Mathematics
1 answer:
Lelu [443]2 years ago
6 0
8-6=2 n=0 your very welcome!
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36 inches, 20 inches, and 24 inches. What type of triangle did Rosa draw?
Rama09 [41]

Answer:

Scalene triangle

Step-by-step explanation:

8 0
3 years ago
A number k is less than 3 units from 10. <br> What's the absolute value inequality???
Brrunno [24]

It would be: k+3 = 10

subtracting 3 from both sides,

k+3-3 = 10-3

k=7

6 0
3 years ago
The length of a rectangle is 8 inches more than three times the width. the perimeter is 88 inches. find the length and width.
Sav [38]
We can say L as length and W as the width 

L= 3w + 8 

The formula for perimeter is 2L + 2W = P. We can substitute L in as "3w+8" to make the equation... 

2(3w+8)+2w=88        Now, we can simplify by distributing the 2 to each term
6w+16+2w=88
8w+16=88               Then subtract 16 from each side..
8w=72
w=9

So the width is 9, so we can substitue that into the previous equation, L = 3w+8. 

L=3(9)+8
L=27+8
L=35, W=9



5 0
2 years ago
The graph of the function f(x) = (x - 3)(x + 1)
djyliett [7]

Answer:

The graph is positive and decreasing for all real values of x where x < -1

Step-by-step explanation:

we have

f(x)=(x-3)(x+1)

The function is a vertical parabola open up

The roots (x-intercepts) are x=3 and x=-1

The vertex is the point (1,-4 ) is a minimum

using a graphing tool

see the attached figure

we know that

In the interval (-∞,-1) ---> the function is positive and decreasing

In the interval (-1,1) ---> the function is negative and decreasing

In the interval (1,3) ---> the function is negative and increasing

In the interval (3,∞) ---> the function is positive and increasing

therefore

The graph is positive and decreasing for all real values of x where x < -1

8 0
3 years ago
Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
2 years ago
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