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ryzh [129]
4 years ago
7

A point P is placed exactly between two charges, Q1 and Q2. If the electric field experienced by point P due to charge Q1 is 1.5

× 105 newtons/coulomb and the field due to charge Q2 is 7.2 × 105 newtons/coulomb, what is the net electric field at point P?
A.
1.5 × 105 newtons/coulomb
B.
3.0 × 105 newtons/coulomb
C.
5.7 × 105 newtons/coulomb
D.
8.7 × 105 newtons/coulomb
E.
9.0 × 105 newtons/coulomb
Physics
1 answer:
iren2701 [21]4 years ago
4 0

<em>Answer:  D</em>

<em>Given data:</em>

The electric field due to charge q₁  is (E₁) = 1.5 × 10⁵ N/C

The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C

Determine the net electric field at point P (Enet) = ?

electric field measured in Newtons/coulomb

<em>We know that,</em>

        The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively

             Enet = E₁ + E₂

                       = (1.5 × 10⁵)+ (7.2 × 10⁵)

                       = 8.7 × 10⁵ Newtons/coulomb

<em>The net electric field at point P is  8.7 × 10⁵ N/C</em>

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