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NemiM [27]
4 years ago
7

Badri makes the table below to review the factors that affect the electric force between objects. Which change will correct the

error in Badri’s table? changing “Direct” to “Indirect” changing “Indirect” to “Direct” changing “Distance” to “Amount of electric charge” changing “Mass” to “Amount of electric charge”
Distance Indirect
Mass Direct
Physics
2 answers:
Veronika [31]4 years ago
5 0

The correct answer is:

D. Changing “Mass” to “Amount of electric charge”.

The change will correct the error in Badri’s table.

|Huntrw6|

kirill115 [55]4 years ago
4 0

Answer:

Changing "Mass" to "Amount of electric charge"

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UPVOTES FOR EVERY ANSWER!!!!!!!!
Goshia [24]
<span>A. The magnetic force increases.

F is inversely proportional to r</span>²<span>

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7 0
3 years ago
Read 2 more answers
What is the current in a wire of radius R = 2.02 mm if the magnitude of the current density is given by (a) Ja = J0r/R and (b) J
Sloan [31]

Explanation:

For this problem we have to take into account the expression

J = I/area = I/(π*r^(2))

By taking I we have

I = π*r^(2)*J

(a)

For Ja = J0r/R the current is not constant in the wire. Hence

I(r) = \pi r^{2} J(r) = \pi r^{2} J_{0}r/R = \pi r^{3} (3.74*10^{4}A/m^{2})/(2.02*10^{-3}m)

and on the surface the current is

I(R) = \pi r^{2} J(R) = \pi r^{2} J_{0}R/R = \pi(2.02*10^{-3})^{2} (3.74*10^{4}) = 0.47 A

(b)

For Jb = J0(1 - r/R)

I(r)=\pi r^{2}J(r) =\pi r^{2} J_{0}(1 - r/R)=\pi r^{2}J_{0}(1-\frac{r}{2.02*10^{-3}} )

and on the surface

I(R)=\pi r^{2}J_{0}(1-R/R)=\pi r^{2}J_{0}(1-1)= 0

(c)

Ja maximizes the current density near the wire's surface

Additional point

The total current in the wire is obtained by integrating

I_{T}=\pi\int\limits^R_0 {r^{2}Ja(r)} \, dr = \pi \frac{J_{0}}{R}\int\limits^R_0 {r^{3}} \ dr =\pi  \frac{J_{0}R^{4}}{4R}=\frac{1}{4}\pi J_{0}R^{3}=2.42*10^{-4} A

and in a simmilar way for Jb

I_{T}=\pi J_{0} \int\limits^R_0 {r^{2}(1-r/R)} \, dr = \pi   J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2R}]=\pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2}]

And it is only necessary to replace J0 and R.

I hope this is useful for you

regards

7 0
3 years ago
A given flow field is defined by streamwise velocity component u = (8x) ft/s and cross-stream velocity component v = (8y) ft/s,
stealth61 [152]
Lol this easy 2+2 and then just add 4 that’s 8 add 3 more that’s 16 if you add 4

420vibesz
3 0
3 years ago
An 80 kg person jumps out of a plane. If the air resistance is 800 N, find the<br><br> Acceleration.
sertanlavr [38]

Answer:

The acceleration is 10 m/s²

Explanation:

The question seeks to show the relationship between force, mass and acceleration. Hence, the formula to be used here is that of force which is shown below

F = ma

where F is the force (800 N)

m is the mass (80 kg)

a is the acceleration (unknown)

From the formula above (Force = mass multiplied by acceleration)

800 N = 80 kg × a

a = 800 ÷ 80

a = 10 m/s²

4 0
3 years ago
Read 2 more answers
A certain material has a mass of 565 g while occupying 50 cm3 of space. What is this material?
EastWind [94]

<u>Answer:</u>

Lead

<u>Explanation:</u>

To get the density of the material, the formula would be:

mass divided by volume which is given by d = \frac { m } { v }.

Here in this problem, we are given a mass of 565 g which occupies a volume of 50 cm^3.

So plugging the data in the above formula to find the density:

Density = \frac { 565 } { 50 } = 11.3

From the table, we can see that the material is Lead which has a density of 11.3c/cm^3.

8 0
3 years ago
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