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3 years ago

How many people aspire to become entrepreneurs if the total is 360 people? Doctor : 65% Police : 5% Pilot : 20% ENTREPENEURS????

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Answer: 36 people

Step-by-step explanation:

1. The number of people that aspire to become doctor is:

360 people*0.65=234 people

2. The number of people that aspire to become police is:

360 people*0.05=18 people

3. The number of people that aspire to become pilot is:

360 people*0.2=72

4. The sum of people that do not aspire to become entrepreneurs is:

234 people+18 people+72 people=324 people

5. Therefore, the number of people that aspire to become entrepreneurs is:

360 people-324 people=36 people

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Help quiz question!!!

SVEN [57.7K]

Answer:301.59389

Step-by-step explanation:

254.47+47.12389=301.59389

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3 years ago

Over what interval is the graph of f(x) = –(x + 8)2 – 1 decreasiang help

Degger [83]

Please use " ^ " to denote exponentiation:

f(x) = –(x + 8)^2 – 1
Find the first derivative: f '(x) = -2(x+8)(1)
Set this = to 0: -2(x+8) = 0
solve for x: x = -8
Divide the number line into subintervals based upon x=-8:

(-inf, -8) and (-8, inf)

Choose a test value for x from each interval, e. g., -10 from the first interval and 20 from the second.

Subst. this test value into the derivative, shown above.

If the result is + the function is incr on that interval; if - the fn. is decr.

Questions welcome!

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3 years ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

For Bus:

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

For motorcycle:

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

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3 years ago

Annika pays 2/25 of her weekly income into a retirement fund. If she pays £42 into the retirement fund, what is her weekly incom

skad [1K]

Answer:

Below.

Step-by-step explanation:

Let x be the Annika's weekly income.

2/25 of x = 42

2x/25 = 42

x = 42(25/2)

x = 525

Her weekly income is $525.

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3 years ago

Determine whether the sequence appears to be an arithmetic sequence. If so, find the common difference and the next three terms

guapka [62]

an aritmetic sequence increases by the same amount each time (if it decreases, then it increases by a negative number)

the common difference is the number that must be added to a term to get the next term

let's see if it increases by the same amount

-5 to -11 is increase of -6

-11 to -17 is increase of -6

-17 to -23 is increase of -6

-23 to -29 is increase of -6

so it appears to be aritmetic

common difference is -6

-29-6=-35

-35-6=-41

-41-6=-47

the next 3 terms are -35, -41, -47

4 0

4 years ago