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3 years ago

Write an equation parallel to the function y=2x+3 and goes through the point (1, -4)

Mathematics

1 answer:

sergey [27]3 years ago

6 0

Answer:

y=2x-6

Step-by-step explanation:

Parallel functions are functions with the same slopes but are in different positions on the coordinate plane (for this case it means that they have different y- intercepts)

So this means that the function will have a slope of 2

To find the equation we must plug in the value (1, -4) and find the new y-intercept(c)

(-4)= 2(1)+c

-4-2=c

-6=c

This means that the parallel function that goes through the point (1,-4) is

y=2x-6

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2 years ago

Read 2 more answers

Write an expression that is equivalent to (3x-2)-x^2+2x+5), combing like terms

ss7ja [257]

Answer:

-x^2+5x+3

Step-by-step explanation:

Remove unnecessary parenthesis.

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-x^2+5x+3

4 0

3 years ago

Please prove this........

Crazy boy [7]

Answer: see proof below

Step-by-step explanation:

Given: A + B + C = π → C = π - (A + B)

→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))

→ sin C = sin (A + B) cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

Proof LHS → RHS

LHS: (sin 2A + sin 2B) + sin 2C

$\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C$

$\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C$

$\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C$

$\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)$

$\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]$

$\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B$

$\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C$

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C $\checkmark$

7 0

3 years ago