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3 years ago

Write an equation parallel to the function y=2x+3 and goes through the point (1, -4)

Mathematics

1 answer:

sergey [27]3 years ago

6 0

Answer:

y=2x-6

Step-by-step explanation:

Parallel functions are functions with the same slopes but are in different positions on the coordinate plane (for this case it means that they have different y- intercepts)

So this means that the function will have a slope of 2

To find the equation we must plug in the value (1, -4) and find the new y-intercept(c)

(-4)= 2(1)+c

-4-2=c

-6=c

This means that the parallel function that goes through the point (1,-4) is

y=2x-6

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castortr0y [4]

Answer:

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Step-by-step explanation:

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3 years ago

The function h(x) = 1/2 (x+3)2 +2. How is the graph of the h(x) translated from the parent graph of a quadratic function, F(x) =

Natali5045456 [20]

For this case, the parent function is given by:
$F (x) = x ^ 2
$
We apply the following function transformation:
Vertical compressions:
To graph y = a * f (x)
If 0 <a <1, the graph of y = f (x) is compressed vertically by a factor a. (Shrinks)
We have then:
$y = (1/2) * x ^ 2
$
Horizontal translations:
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
$y = (1/2) * (x + 3) ^ 2
$
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
We have then:
$h (x) = (1/2) * (x + 3) ^ 2 + 2
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3 years ago

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Vlad1618 [11]

Answer:

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Step-by-step explanation:

We know that the total weight the farmer sold was 8.9 kilograms.

- 3/4 of this weight is apples, and the rest is pears.

Therefore, to calculate the amount of kilograms of pears she sold at the farmer's market (which you can call x), you need to apply the following procedure.

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