Table C since it is decreasing at a constant rate of 5.
55 - 5 = 50
50 - 5 = 45
45 - 5 = 40
ANSWER
![2{m}^{3}](https://tex.z-dn.net/?f=%202%7Bm%7D%5E%7B3%7D%20)
EXPLANATION
The expressions are
![8 {m}^{3} = {2}^{3} \times {m}^{3}](https://tex.z-dn.net/?f=8%20%7Bm%7D%5E%7B3%7D%20%20%3D%20%20%7B2%7D%5E%7B3%7D%20%20%5Ctimes%20%20%7Bm%7D%5E%7B3%7D%20)
and
![6 {m}^{4} = 2 \times 3 {m}^{4}](https://tex.z-dn.net/?f=6%20%7Bm%7D%5E%7B4%7D%20%20%3D%202%20%5Ctimes%203%20%7Bm%7D%5E%7B4%7D%20)
The greatest common factor is the product the least powers of the common factors.
![= 2 {m}^{3}](https://tex.z-dn.net/?f=%20%3D%202%20%7Bm%7D%5E%7B3%7D%20)
Assuming that the two investments are X & Y
X + Y = 6300
X = 6300 - Y (1)
9/100X + 4/100 Y = 372 (2)
replacing X from (1) into (2)
9/100(6300-Y) + 4/100 Y = 372
567 - 9/100Y +4/100Y = 372
(-9+4)/100Y = 372 - 567
5/100Y = -195
Y = 100*195/5 = 3900
From (1) we can get X
X = 6300 - 3900 = 2400
I hope this is helpful
This is the concept of rates, we are required to convert on rate to another. The We have been given a car that is speeding at 9595 mph, we are required to convert this to meters per minute;
Here we proceed as follows;
1 mile= 1609.34 miles/hour
1 hour= 60 min
thus to convert from miles per hour to meters per minute we shall have:
speed=distance/time
our distance will be:
distance=9595*1609.34=15,441,617.3 meters
time=(60*1)=60 minutes
thus;
speed=15,441,617.3/60
speed=257,360.2882 meters per minuts