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borishaifa [10]
4 years ago
13

Difen Amniotic fluid?​

Biology
2 answers:
guajiro [1.7K]4 years ago
8 0

<em><u>Amniotic</u></em><em><u> </u></em><em><u>fluid</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>fluid</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>surrounds</u></em><em><u> </u></em><em><u>fetus</u></em><em><u> </u></em><em><u>within</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>amnion</u></em><em><u>.</u></em>

<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em>

Inessa05 [86]4 years ago
8 0
The amniotic fluid is the protective liquid contained by the amniotic sac of a gravid amniote. This fluid serves as a cushion for the growing fetus, but also serves to facilitate the exchange of nutrients, water, and biochemical products between mother and fetus.
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Describe in order the steps in the life cycle of a seed-bearing plant, which reproduces sexually.
marishachu [46]
I would say polon because it is how it reproduce's
6 0
3 years ago
Do all human cells obtain glucose in the same way 
kipiarov [429]

Answer:

Animal cells (including humans ofcourse), heterotrophs, derive their energy from coupled oxidation-reduction reactions. Glucose is a primary fuel for heterotrophs. Energy derived from glucose is stored in the form of high-energy phosphate bonds in ATP, or other nucleotide triphosphates, and as energy-rich hydrogen atoms associated with the co-enzymes NADP and NAD .

Glucose is unable to diffuse across the cell membrane without the assistance of transporter proteins. At least 13 hexose transporter proteins with different functions have been identified. Some hexose transporters allow glucose to flow passively from high to low concentration without requiring the expenditure of cell energy. Those that move glucose against its concentration gradient consume energy, generally in the form of ATP.

D-Glucose is the natural form used by animal cells.

So yes it is present inside human cells .

5 0
1 year ago
Imagine that you attempted to recreate Mendel's work with garden peas. You began by crossing true breeding violet-flowered, tall
salantis [7]

Answer:

(a) 90

(b) 30

(c) 30

(d) 10

F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation.

F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment

Explanation:

The F2 phenotypes are supposed to be in 9:3:3:1 according to Mendelian law. The total number of F2 progeny is: 80 + 36 + 39 + 5 = 160

(a) Hence, the expected number of tall, violet plants will be:

            9/16 x 160 = 90

(b) Expected number of tall, white plants will be:

            3/16 x 160 = 30

(c) Expected number of dwarf, violet plants will be:

            3/16 x 160 = 30

(d) Expected number of dwarf, white plants will be:

            1/16 x 160 = 10.

Total number of tall F2 plants = 80 + 36 = 116

Total number of dwarf F2 plants = 39 + 5 = 44

Expected ratio of tall:dwarf plants according to Mendel = 3:1

Expected number of tall plants = 3/4 x 160 = 120

Expected number of dwarf plants = 1/4 x 160 = 40

Chi square X^2

= \frac{(observed frequency - expected frequency)^2}{expected frequency}

X^2 for tall = \frac{(116 - 120)^2}{120}

                                    = 0.1333

X^2 for dwarf = \frac{(44 - 40)^2}{40}

                                      = 0.40

Total X^2 = 0.1333 + 0.4

                                    0.5333

Degree of freedom = n - 1

                                   2 - 1 = 1

Tabulated X^2 (α = 0.05) = 3.841

Since the tabulated X^2 is more than the calculated X^2, the hypothesis that the F2 data for stem length (tall:dwarf) is consistent with Mendel's law of segregation is accepted.

                                       Observed    Expected    X^2

tall, violet flowers                  80          90         \frac{(80-90)^2}{90} = 1.11

tall, white flowers                36            30          \frac{(36-30)^2}{30} = 1.2

dwarf, violet flowers             39           30         \frac{(39-30)^2}{30} = 2.7

dwarf, white flowers            5              10         \frac{(5-10)^2}{10} = 2.5

       Total                             160           160                       7.51

Degree of freedom = 4 - 1 = 3

Tabulated X^2 (α = 0.05) = 7.815

The tabulated X^2 value is more than the calculated X^2 value. Hence, F2 data for stem length (tall:dwarf) and flower color (violet:white) is consistent with Mendel's law of independent assortment.            

3 0
3 years ago
Plants obtain their organic nutrients (carbon, hydrogen, and oxygen) by:
viktelen [127]

Answer:

photosynthesis

Explanation:

plants can absorb most if not al of the things through their leaves alone to get organic nutrients. The roots are for more less organic nutrients like fertilizer etc...

7 0
4 years ago
Read 2 more answers
How many units of energy would there need to be in the first trophic level to end up with 1000 units of energy in the second? in
Anestetic [448]

Answer:

(First) 10,000--->1000--->100-->10 (fourth)

Explanation:

Each trophic levels gets reduced by factor of 10.

Thus if you start with 10,000 in first, then you end with 1000 in second, 100 in third and 10 in forth.

3 0
2 years ago
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