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adelina 88 [10]
4 years ago
7

Suppose that blood chloride concentration (mmol/L) has a normal distri- bution with mean 104 and standard deviation 5 (informati

on in the article \Mathematical Model of Chloride Concentration in Human Blood," J. of Med. Engr. and Tech., 2006: 25{30, including a normal probability plot as described in Section 4.6, supports this assumption).
What is the probability that chloride concentration di ers from the mean by more than 1 standard deviation?
Mathematics
1 answer:
Andreyy894 years ago
5 0

Answer:

32% probability that chloride concentration differs from the mean by more than 1 standard deviation

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

What is the probability that chloride concentration di ers from the mean by more than 1 standard deviation?

By the Empirical Rule, there is a 68% probability that the chloride concentration differs from the mean by one standard deviation or less.

100 - 68 = 32.

32% probability that chloride concentration differs from the mean by more than 1 standard deviation

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What is the following product?<br><br>A: –2<br>B: 2<br>C: 22 – 40√6<br>D: 98 – 40√6
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3 years ago
Simplify: -3 1/2(-12 1/4)
pshichka [43]

Answer:

26 \frac{1}{4}

Step-by-step explanation:

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Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

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In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

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Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

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Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

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Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
4 years ago
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