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stealth61 [152]
3 years ago
11

How can I tell if a triangle with side lengths 10, 24, and 26 is a right triangle?

Mathematics
1 answer:
Alex777 [14]3 years ago
4 0
10^2 +24^2 =26^2
=676
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How would I solve this?
zvonat [6]
Use Pythagorean Theorem which states that in a right triangle:

 a^2+b^2=c^2, where a and b are the legs, and c is the hypotenuse.

24^2+10^2=x^2

Take the square root of both sides to solve for x.

x =  \sqrt{676} = 26

The answer  is 26.


4 0
3 years ago
Please help urgent!!!!! <br><br> Will mark brainlest or something like that
r-ruslan [8.4K]

Answer:

im sry could u pls rewrite the expression?

Step-by-step explanation:

4 0
2 years ago
Which of the following functions is graphed below?
Pie

Answer:

C

Step-by-step explanation:

C is the solution

7 0
3 years ago
Read 2 more answers
Solve the inequality of c=20x+19,152 r=24x
Alex Ar [27]
The answer is there with the attached peice

6 0
3 years ago
Given f'(x)=(x-4)(6-2x) find the x-coordinate for the relative minimum of the graph f(x).
vlabodo [156]
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>

Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get

f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24

So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5

<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5

The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.

So the final answer is C) 3
5 0
3 years ago
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