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icang [17]
3 years ago
5

HELP ME PLEASE!!!!!!

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0
I realise this is quite late but in case you still wanted the answer, the width is 3m.

If the length is 3m longer than the width, you can write the width as x and the length as x + 3. The perimeter would be both lengths and both widths added together, so you would just write it as:
x + x + x + 3 + x + 3 = 18
4x + 6 = 18
- 6
4x = 12
÷ 4
x = 3

I hope this helps!
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During their first home game, the Eagles soccer team drew a total of 176 fans. By the second game, this number grew to 202 fans.
vazorg [7]

Answer:

Step-by-step explanation:

Initial # = 176 fans

Final # = 202 fans

Increase = 202 - 176 = 26 fans

% increase = 100% x (Increase / initial #)

= 100 x (26/176)

= 100 x 0.1477

= 14.78%

5 0
3 years ago
Find the value of x and the measure of the angle labeled 3x
mafiozo [28]

Answer:

27

Step-by-step explanation:

45+27=72 and the overall angle is 72

5 0
3 years ago
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Can someone tell me what’s going on here
lora16 [44]

Answer:

c = 105 degres

Step-by-step explanation:

When two lines cross like that and form an x, the opposite sides are equal (so the angle below the 75 degree one is also 75 degees). Using this, you can figure out the rest.

If both the top an bottom are equal, you know that 150 degres are taken (75+75) and you know that there can only be 360 degres in total here, so you subtract 150 from 360 and get 210. Now you know that the last two sides together are 210, and since they are equal, you divide it by two to get 105 degrees.

8 0
3 years ago
Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = 2x2 + 4x –3
egoroff_w [7]
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8 0
3 years ago
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Multiple choice question?
nydimaria [60]

Answer:

9* 3 ^ (x-2)

Step-by-step explanation:

g(x) = 3^x

We know a^ (b) * a^(c) = a^ (b+c)

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3*(9^(x+2)) = 3*3^2(x+2) = 3^1 * 3^(2x+4) =3^(2x+4+1) = 3^(2x+5) not equal  

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3*(9^(x-2)) = 3*3^2(x-2) = 3^1 * 3^(2x-4) =3^(2x-4+1) = 3^(2x-3) not equal        

6 0
3 years ago
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