Answer:
a^2 +b^2=c^2
Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)
We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2
) is given by m= x 2−x 1
y
2
−y
1
,x
2
=x
1
Slope of AB i.e.m
1
=
3−4
5−4
=−1
Slope of BC i.e.m
2
=
−1−3
−1−5
=
−4
−6
=
2
3
Slope of CA i.e. m
3
=
4+1
4+1
=
5
5
=1
Clearly, m
1
m
3
=−1
⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).
Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.
Step-by-step explanation:
Answer:
q = 
Step-by-step explanation:
Given
5(q + p) = 4 + 8p ← distribute the left side
5q + 5p = 4 + 8p ( subtract 5p from both sides )
5q = 4 + 3p ( divide both sides by 5 )
q =
60 inches because the square has 4 sides so 4x2 is 8 and 52+8 is 60.
Answer:
56% ≤ p ≤ 70%
Step-by-step explanation:
Given the following :
Predicted % of votes to win for candidate A= 63%
Margin of Error in prediction = ±7%
Which inequality represents the predicted possible percent of votes, x, for candidate A?
Let the interval = p
Hence,
|p - prediction| = margin of error
|p - 63%| = ±7%
Hence,
Upper boundary : p = +7% + 63% = 70%
Lower boundary : p = - 7% + 63% = 56%
Hence,
Lower boundary ≤ p ≤ upper boundary
56% ≤ p ≤ 70%
