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RideAnS [48]
2 years ago
14

How much larger is 27 than 6

Mathematics
2 answers:
grigory [225]2 years ago
6 0

Answer:

21

Step-by-step explanation:

27-6=21

irinina [24]2 years ago
3 0

Answer:

21

Step-by-step explanation:

27-6=21, so this means that 27 is 21 points higher than 6.

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I learn maths and I don't know how to solve this problem.
Lyrx [107]

Answer:

As we get closer to x=-3, the limit is approaches -1, on both sides of -3 so this is a good limit so c is 8.

Step-by-step explanation:

In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.

In this case, this a piece wise function and by definition of a limit that exist, the limit of this piece wise function as x approaches 3 from either side, must be equal.

We let x=-3 for the top equation.

( - 3) {}^{2}  - 10 =  - 1

So we set the second equation equal to -1.

- ( {x}^{2} ) + c =  - 1

- ( - 3 {}^{2} ) + c =  - 1

- 9 + c =  - 1

c = 8

So the value of c is 8. We can prove this by graphing as well.

5 0
2 years ago
.(09.08HC)<br> Prove that the two circles shown below are similar.
Leni [432]
Both circles middles are positive
8 0
3 years ago
Predict how much money can be saved without having a negative actual net income.
satela [25.4K]

$170 can be saved resulting in an actual net income of $0.

6 0
3 years ago
Please tell me where to graph this!! (include if i open circle or not please) (NO FILE ANSWER!!!)
3241004551 [841]

Answer:

1.Make the circle open

2.put the dot on 5

3. change direction

Step-by-step explanation:

A solid dot on a number line graph indicates that the given number should be included as a possible solution, whereas an open dot indicates that the given number cannot be a solution. For example, if you graph x > 7, you place an open dot at 7.

Have a nice day! :-)

7 0
3 years ago
Read 2 more answers
Solve x^2 - x = 2 using the quadratic formula. Show your work.
lesya [120]
The quadratic formula is the result of completing the square for ax^2+bx+c=0 when a,b, and c are unknown values.  This result is:

x=(-b±√(b^2-4ac))/(2a), we have x^2-x-2=0 so

x=(1±√(1+8))/2

x=(1±√9)/2

x=(1±3)/2

x=-1 and 2
8 0
3 years ago
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