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3 years ago

How much larger is 27 than 6

Mathematics

2 answers:

grigory [225]3 years ago

6 0

Answer:

Step-by-step explanation:

27-6=21

irinina [24]3 years ago

3 0

Answer:

Step-by-step explanation:

27-6=21, so this means that 27 is 21 points higher than 6.

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A manufacturing plant is capable of producing 10 tons of product per day when it runs three shifts with no breakdowns and plenty

Temka [501]

Answer: 73%

Step-by-step explanation:

The plant is capable of producing 10 tons of product in one day.

Currently however, it is only able to produce 7.3 tons per day.

Utilization is therefore:

= Actual production/ Potential production * 100

= 7.3/10 * 100

= 73%

3 0

3 years ago

Which shows the graph of the solution set of x + 2y > 4?

nata0808 [166]

we have

$x+2y > 4$

The solution is the shaded area above the dotted line

therefore

The answer in the attached figure

7 0

4 years ago

Read 2 more answers

HELP PLSS!!

erma4kov [3.2K]

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 3, 6 ] , then

f(b) = f(6) = 6² + 3(6) + 2 = 36 + 18 + 2 = 56

f(a) = f(3) = 3² + 3(3) + 2 = 9 + 9 + 2 = 20 , then

average rate of change = $\frac{56-20}{6-3}$ = $\frac{36}{3}$ = 12

8 0

3 years ago

6w+3+9-2n use w=3 and n=2

Readme [11.4K]

Answer:

Step-by-step explanation:

from what I got lol , your welcome and have a nice day

3 0

3 years ago

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations. Hint: Use

QveST [7]

$\bf 27\implies 3^3\\\\
i^3\implies i\cdot i\cdot i\implies i^2\cdot i\implies -1\cdot i\implies -i\\\\
-----------------------------\\\\
x^3-27i=0\implies x^3+3^3(-i)=0\implies x^3+(3^3i^3)=0
\\\\\\
x^3+(3i)^3=0\\\\
-----------------------------\\\\
\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3\\\\
-----------------------------\\\\$

$\bf (x+3i)[x^2-3ix+(3i)^2]=0\implies 
\begin{cases}
x+3i=0\implies \boxed{x=-3i}\\\\
x^2-3ix+(3i)^2=0
\end{cases}
\\\\\\
\textit{now, for the second one, we'd need the quadratic formula}
\\\\\\
x^2-3ix+(3i)^2=0\implies x^2-3ix+(3^2i^2)=0
$

$\bf x^2-3ix+(-9)=0\implies x^2-3ix-9=0
\\\\\\
\textit{quadratic formula}\\\\
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\implies x=\cfrac{3i\pm\sqrt{(-3i)^2-4(1)(-9)}}{2(1)}
\\\\\\
x=\cfrac{3i\pm\sqrt{(-3)^2i^2+36}}{2}\implies x=\cfrac{3i\pm\sqrt{-9+36}}{2}
\\\\\\
x=\cfrac{3i\pm\sqrt{27}}{2}\implies \boxed{x=\cfrac{3i\pm 3\sqrt{3}}{2}}$

7 0

3 years ago