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Brilliant_brown [7]
3 years ago
15

Please help don’t understand

Mathematics
1 answer:
sergejj [24]3 years ago
8 0

Answer:

x=35

Step-by-step explanation:

2x+15+2x-10+x=180

combine factors

5x+5=180

-5 from both sides

5x=175

divide 175/5x

x=35

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Five times the difference of twice a number and three, decreased by the sum of the number and eight, equals 13
denis23 [38]
5(2x-3)-(x+8)=13
10x-15-x-8=13
9x-23=13
9x=36
x=4
7 0
3 years ago
Read 2 more answers
The sum of a number and 8 is inore than 4.
marta [7]

Hey there!

Guide:

• The word “sum” means “add”

• The word “difference” means “subtract”

• The word “product” means “multiply”

• The word “quotient” means “divide”

• The word “is” means “equal”

• The word “more-than” can either mean “add” or “bigger than”. It is a number that is bigger than the number compared to (like 6 is bigger than 5)

• The word “less-than” can either mean “subtract” or “smaller than”. It is a number that is being is smaller than the number that it is being compared to (like 5 is smaller than 6)

Guide 2:

• > is greater than / more than

• < is less than

• + is sum

• - is difference

• × is product or “of”

• ÷ is quotient

• ≥ is greater than or equal to whereas it is either greater than or equivalent to the numbers that are being compared

• ≤ is less than or equal to where is either less than or equivalent to the numbers that are equivalent to each other

Now that we have that information out of the way, we can answer you question.

We have the words: “sum” and “is” in your mathematical word expression, we know that we’re ADDing and trying to figure out what is GREATER than 4.

Your “number” that is being compared to “8” is unknown so we will label it as “z” as it’s variable.

Anyways let’s answer your question

“The sum of a number and 8”

z + 8

“Is more than 4”

> 4

YOUR EQUATION: “z + 8 > 4” (POSSIBLE ANSWER #1)

SOLVING FOR YOUR EQUATION:

z + 8 > 4

SUBTRACT 8 to BOTH SIDES

z + 8 - 8 > 4 - 8

CANCEL out: 8 - 8 because it gives you 0

KEEP: 4 - 8 because it helps you figure out what is being compared to the z-value.

z > 4 - 8

SIMPLIFY IT!

z > -2 (POSSIBLE ANSWER #2)

It is an OPEN circle shaded to the RIGHT side of the number line starting at -4. (Factoid for POSSIBILITY #2)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

4 0
2 years ago
Find the inverse function for f(x) = cubic root sqrt x+2
dalvyx [7]

we are given

f(x)=\sqrt[3]{x+2}

Firstly , we set f(x)=y

y=\sqrt[3]{x+2}

now, we can switch x and y

x=\sqrt[3]{y+2}

now, we can solve for y

x^3=(\sqrt[3]{y+2})^3

x^3=y+2

y=x^3-2

so, our inverse function is

f^{-1}(x)=x^3-2............Answer

6 0
4 years ago
Read 2 more answers
HARDEST MATH QUESTION IN EXISTENCE. CAN YOU ANSWER?
Svetach [21]

Answer:

The answer is 1.2

Step-by-step explanation:

u add 2.2 and 1.2 which you get 3.4. The difference is 1.2.

8 0
3 years ago
Perform the indicated operation. Simplify the result in factored form.
vfiekz [6]

Answer:

\frac{a+1}{(a-2)(a-1)(a-1)}=

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to factor the expression. In order to subtract (or add) two fractions, both fractions have to have common denominators. When the fractions are factored one can easily see the least common denominator. Convert both fractions to the least common denominator by multiplying the numerator (number over the fraction bar) and denominator (number under the fraction bar) by the value such that both fractions have the same denominator. Finally, one can subtract the numerators of the two fractions.

2. Factoring and Least common denominator

\frac{3}{a^2-3a+2}-\frac{2}{a^2-1}=

Factor the expression, rewrite the quadratic polynomials as the product of two linear polynomials,

\frac{3}{a^2-3a+2}-\frac{2}{a^2-1}=

\frac{3}{(a-2)(a-1)}-\frac{2}{(a-1)(a+1)}=

The least common denominator is: ((a-2)(a-1)(a-1))

Convert both fractions to the least common denominator, multiply both the numerator and denominator by the same value to do so,

\frac{3}{(a-2)(a-1)}-\frac{2}{(a-1)(a+1)}=

\frac{3}{(a-2)(a-1)}*\frac{a-1}{a-1}-\frac{2}{(a-1)(a+1)}*\frac{a-2}{a-2}=

Simplify,

\frac{3}{(a-2)(a-1)}*\frac{a-1}{a-1}-\frac{2}{(a-1)(a+1)}*\frac{a-2}{a-2}=

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

3. Solving the expression

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

Distribute, multiply every term inside the parenthesis by the term outside of it,

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

\frac{3a-3}{(a-2)(a-1)(a-1)}-\frac{2a-4}{(a-1)(a+1)(a-2)}=

Simplify further,

\frac{3a-3}{(a-2)(a-1)(a-1)}-\frac{2a-4}{(a-1)(a+1)(a-2)}=

\frac{3a-3-(2a-4)}{(a-2)(a-1)(a-1)}=

\frac{3a-3-2a+4}{(a-2)(a-1)(a-1)}=

Combine like terms,

\frac{3a-3-2a+4}{(a-2)(a-1)(a-1)}=

\frac{a+1}{(a-2)(a-1)(a-1)}=

4 0
3 years ago
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