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Complete question:
Rory records the percentage of battery life remaining on his phone throughout a day. The graph represents the percentage of battery life remaining after a certain number of hours.
Rory’s battery was full at 6:00 a.m, or t = 0. Which times could Rory's phone have been plugged into the charger? Select three options.
12:00 p.m.
3:00 p.m.
5:00 p.m.
8:00 p.m.
11:00 p.m.
The graph is attached
Answer:
3:00 p.m
5:00 p.m
11:00 p.m
Step-by-step explanation:
From the graph, there are rise times, fall times and there are times the movement is steady (no rise or fall).
The rise time represents the time the phone was plugged. The fall time represents when the charger has been unplugged so the battery level starts depreciating. When it is constant, it means the battery level is at 100 but the charger is still connected to the phone.
We are told at initial condition, time was 6 a.m (t = 0). To get the exact time, we are to add the initial condition, i.e 6
From the graph, the times the phone could have been plugged are 8:00 to 12:00 hrs and 16:00 to 20:00 hrs.
Converting from 24 hr to 12 hr time, we have:
6 + 8hrs = 14:00 = 2:00 p.m
6 + 9hrs = 15:00 = 3:00 p.m
6 + 10 hrs = 16:00 = 4:00 p.m
6 + 11 hrs = 17:00 = 5:00 p.m
6 + 12 hrs = 18:00 = 6:00 p.m
6 + 16 hrs = 22:00 = 10:00 p.m
6 + 17 hrs = 23:00 = 11:00 p.m
6 + 18 hrs = 00:00 = 12:00 am
6 + 19 = 1 : 00 = 1:00 a.m
6 + 20 = 2:00 = 2:00 a.m
From the options given in the question, we have:
3:00 p.m; 5:00 p.m; 11:00 p.m
Therefore, times could Rory's phone have been plugged into the charger are:
3:00 p.m
5:00 p.m
11:00 p.m
Answer is 54^2.
since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.
the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.
all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36
now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3
the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36
add all the numbers you got now for each boundary and that would be your area squared.
6+9+3+36=54^2
so your final answer is 54^2.
i hope this helps you.
since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.
the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.
all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36
now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3
the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36
add all the numbers you got now for each boundary and that would be your area squared.
6+9+3+36=54^2
so your final answer is 54^2.
i hope this helps you.