we
know that if we have a polynomial with real coefients and one root is
a+bi, another root is a-bi
so
some
roots are
3,-4,6+5i,
6-5i
for
roots, r1 and r2
teh
factors are
(x-r1)(x-r2)
so
we
can put them in and
(x-3)(x+4)(x-6-5i)(x-6+5i)
(x^2+x-12)(2x^2-12x+61)
x^4-11x^3+37x^2+205x-732
to
keep the same coefients, we multiply whole thing by c
c(x^4-11x^3+37x^2+205x-732)
we
don't know what c is
we
know that
f(1)=250
f(1)=c(x^4-11x^3+37x^2+205x-732)
find
c
f(1)=c(1^4-11(1^3)+37(1^2)+205(1)-732)=250
f(1)=c(-500)=250
-500c=250
divide
both sides by -500
c=-1/2
the
polynomial (factored with real coefients) is
f(x)=-0.5(x-3)(x+4)(2x^2-12x+61)
Answer:
( x+10)-3= 2
x+10= 5
x= -5
3x+12= 3
3x= -9
x= -3
3( x+6 )= 5x
3x+ 18 = 5x
2x= 18
x =9
w= l-4 y= x-4
perimeter= 2l+ 2w
2(2x) + 2( x-4)
4x+2x-8 = 72
6x= 72+8
6x= 80
x= 13.3 width = 9.3 length = 13.3
4x=48
x = 12
each 2= 24
Answer:
x = 3 and y=4
Step-by-step explanation:
apply elimination method in simultaneous equations
Answer: D
Step-by-step explanation:
She uses a sample size of n=200, and 50% of all customers would actually buy coffee.
2/3 this would be what each child receives
