Isosceles triangle measures 120 degrees which other angles could be in that isosceles triangle

In parallelogram PQRS, find the value of angle SPR if angle RSP is 75° and angle PRS is 39°.

Mazyrski [523]

The two angles given are two angles of a triangle, so the third angle must be:

SPR=180-RSP-PRS

SPR=66°

4 0

3 years ago

Area help hellllppppp

slega [8]

Answer:

Area = 14¹/16 yd² or 14.0625 yd²

Step-by-step explanation:

2. The figure given is a square having equal sides of 3¾ yd each.

Formula for area of the square = a²

Where,

a = 3¾ yd

Plug in the value into the equation:

Area = (3¾)²

Change to improper fraction

Area = (15/4)²

Area = 225/16

Area = 14¹/16 yd² or 14.0625 yd²

8 0

2 years ago

The formula for the area of a circle is A = r 2. Classify the area of a circle with a radius of 0.75 centimeters as either ratio

OlgaM077 [116]

First:The area of a circle is πr squared. Not r2
Second. The area of the circle HAS to be irrational because π is an irrational number. The answer would be, if solved for a circle with the radius of 0.75, the area would be 0.5625π, which is irrational.

6 0

3 years ago

8-35. Use your knowledge of polygons to answer the questions below, if possible.

Nataliya [291]

Answer:

(a)I. 13 Sides II. 7 Sides

(b) 4 Sides, Square

(c)x=52 degrees

(d)x=107 degrees

(e)1620 degrees

Step-by-step explanation:

(a)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

I. If the Interior angle is $1980^0$

Then:

$(n-2)180^0=1980^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=11\\$Add 2 to both sides of the equation\\n-2+2=11+2\\n=13$

The polygon has 13 sides.

II. If the Interior angle is $900^0$

Then:

$(n-2)180^0=900^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=5\\$Add 2 to both sides of the equation\\n-2+2=5+2\\n=7$

The polygon has 7 sides.

(b)The sum of the exterior angle of a polygon is 360 degrees,

Each exterior angle of a n-sided regular polygon is: $\frac{360^0}{n}$

If the exterior angle of a regular polygon is 90°

Then:

$90\°=\frac{360^0}{n}\\ 90n=360\\n=4$

The regular polygon has 4 sides and it is called a Square.

(c)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

Each Interior angle of a regular n-sided polygon is: $\frac{(n-2)180^0}{n}$

For a pentagon, n=5

Then:

$\frac{(5-2)180^0}{5}=2x+4\\108=2x+4\\108-4=2x\\104=2x\\x=52^0$

(d)The sum of the exterior angle of a polygon is 360 degrees.

If four of the exterior angles of a pentagon are 57, 74, 56, and 66.

Let the fifth angle=x

Then:

$57+74+56+66+x=360^0\\253+x=360\\x=107^0$

(e)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

In an 11-gon., n=11

Therefore, the sum of the interior angle=(11-2)180= $1620^0$

The sum of the interior angle does not change either in a regular or irregular polygon.

3 0

2 years ago

PLZ HELP MEH WITH MATH XD

irina [24]

To add any fraction You need to make sure that the denominator of the fractions are same. ( denominator in your sum is 19 )

10/19 + 3/19 ( we have the same denominator )
we can also write this problem like
( 10 + 3 ) / 19 { add the numerators together }
13 / 19

So correct option is B.

hope this helped.. :)

6 0

3 years ago

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