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3 years ago

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A right circular cylinder has a base radius of 5 centimeters and a height of 12 centimeters. What is the volume of this cylinder

?

1 answer:

Nitella [24]3 years ago

6 0

The formula of a cylinder is V=πr^2 h
The radius is 5cm and the height is 12cm

V=π5^2 12
V=300π cm cubed

Your answer is B) V=300π cm cubed

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This is your question

LenaWriter [7]

Answer:
See below.

Step-by-step explanation:
Cinder cone volcanoes = 13
Shield volcanoes = 18
Stratovolcanoes = 6

Total number of volcanoes:
= 13 + 18 + 6
= 37

________________
P (cinder cone):
13/37 = 0.35

P (shield):
18/37 = 0.49

P (stratovolcano)
6/37 = 0.17

Hope it helps ⚜

5 0

2 years ago

In a 180-kilogram sample of ore, there was 3.2% metal. How many kilograms of metal were in the sample?

shtirl [24]

5.76 KG as 180 x 0.032 (3.2 percent) = 5.76

7 0

3 years ago

Create and solve a system of equations for the following scenario: Luke and Leia are selling hot dogs and hamburgers at a minor

mixas84 [53]

So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.

5 0

4 years ago

Martin’s neighbors pay him $8 per week to walk their dog. He saves his money for 5 weeks. Martin buys a new bike helmet for $37.

elena55 [62]

Answer:

8*5=40

so 40-37=3

$3left

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel

Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

<em> The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor </em>

$\bf e^{\int {0.1dt}}=e^{0.1t}$

so its general solution is

$\bf v(t)=Ce^{-0.1t}+100$

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

$\bf \boxed{v(t)=-100e^{-0.1t}+100}$

what is the terminal velocity?

The terminal velocity is

$\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec$

How long before the object reaches 90% of terminal velocity?

90% of terminal velocity = 90 m/sec

we look for a t such that

$\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec$

How far has it fallen by that time?

The distance traveled after t seconds is given by

$\bf \int_{0}^{t}v(t)dt$

So, the distance traveled after 23.026 seconds is

$\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt$

3 0

3 years ago