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2 years ago

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A right circular cylinder has a base radius of 5 centimeters and a height of 12 centimeters. What is the volume of this cylinder

?

1 answer:

Nitella [24]2 years ago

6 0

The formula of a cylinder is V=πr^2 h
The radius is 5cm and the height is 12cm

V=π5^2 12
V=300π cm cubed

Your answer is B) V=300π cm cubed

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Find an expression for a cubic function f if f(4) = 96 and f(-4) = f(0) = f(5) = 0. Part 1 of 4 A cubic function generally has t

Bezzdna [24]

Given a polynomial $p(x)$ and a point $x_0$ , we have that

$p(x_0) = 0 \iff (x-x_0) \text{\ divides\ } p(x)$

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

$(x+4)(x)(x-5) = x(x+4)(x-5)$

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

$f(x) = ax(x+4)(x-5),\quad a \in \mathbb{R}$

To fix the correct value for a, we impose $f(4)=96$ :

$f(4) = 4a(4+4)(4-5) = -32a = 96$

And so we must impose

$-32a=96 \iff a = -\dfrac{96}{32} = -3$

So, the function we're looking for is

$f(x) = -3x(x+4)(x-5)=-3x^3+3x^2+60x$

4 0

3 years ago

36 of 80 marbles are blue. What percent of the marbles are blue

Masja [62]

If 36 of 80 marbles are blue, then the percent of marbles that are blue is 44% i think

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3 years ago

Read 2 more answers

You charge $5 plus $0.75 per dog you walk at a dog shelter. You earn $14 total working on a Saturday. How many dogs did you walk

san4es73 [151]

Answer: You walked 12 dogs

Step-by-step explanation:

If you charge 0.75 per dog then we can represent that by the expression 0.75x where x is the number of dogs. If you charge $5 for the initial amount, then the whole expression will be 0.75x +5 and that has to equal the amount that you earned working on Saturday.So the equation will be

0.75x + 5 = 14 Now solve for x by first subtracting 5 from both sides

-5 -5

0.75x = 9 Divide both sides by 0.75

x = 12

8 0

3 years ago

Divide £945 in the ratio 2:5

dybincka [34]

The answer is 675. 2270. 657

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3 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago