How many times does 3 go into 28? let's see 28÷3 is 9.333 so...9 whole times, thus 9 * 3 is 27 so
a) –a + b is negative
b) a – b is positive
c) b-a is negative
Step-by-step explanation:
1. Suppose a and b are real numbers where a > 0 and b < 0.
a. Is –a + b positive or negative. Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
–a + b
= -(6)+(-5) = -6-5 = -11
So, –a + b is negative
b. Is a – b positive or negative? Explain how you know.
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
a - b
=6-(-5) = 6+5 = 11
So, a – b is positive
c. Is b – a positive or negative. Explain how you know
We know a > 0 and b < 0. so, let a =6 and b = -5
Putting values:
b-a
=(-5)-(6)
= -5-6
= -11
So, b-a is negative
Keywords: Solving Integers:
Learn more about solving integers at:
#learnwithBrainly
Answer: 109.1 degrees
Step-by-step explanation:
To find the angle between the given vectors, we will use the formula below:
Cos(θ) = (U.V)/ |U|.|V|
Where
U = 13i - 8j
V = 2i + 9j
U.V = (2x13) + (-8×9)
U.V = 26 - 72
U.V = - 46
|U| = sqrt ( 13^2 + 8^2)
= sqrt ( 233) = 15.264
|V| = sqrt( 2^2 + 9^2)
= sqrt ( 85 ) = 9.22
Substitute all the value of the parameters into the formula
Cos ø = -46 / (15.3 × 9.2)
Cos ø = - 46 / 140.72
Cos Ø = - 32687
Find the cos inverse of the value
Ø = cos^-1( -32687)
Ø = 109.079 degrees
Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees
Answer:
a) 5.83 cm
b) 34.45°
Step-by-step explanation:
a) From Pythagoras theorem of right triangles, given right triangle ABC:
AB² + BC² = AC²
Therefore:
AC² = 5² + 3²
AC² = 25 + 9 = 34
AC = √34
AC = 5.83 cm
b) From triangle ACD, AC = 5.83 cm, AD = 4 cm and ∠A = 90°.
From Pythagoras theorem of right triangles, given right triangle ACD:
AD² + AC² = DC²
Therefore:
DC² = 5.83² + 4²
DC² = 34 + 16 = 50
DC = √50
DC = 7.07 cm
Let ∠ACD be x. Therefore using sine rule:
190mph
I used speed calculator with advanced mode
HTTP://www.omnicalculator.com/everyday-life/speed
