50000+4000+600+20+5 is the answer.
Answer:3x+5
Step-by-step explanation:
Answer:
80 labels
Step-by-step explanation:
The number of packages are 16 envelopes and 20 envelopes
We solve using LCM Method
We find the Multiples of 16 and 20
Multiples of 16:
16, 32, 48, 64, 80, 96, 112
Multiples of 20:
20, 40, 60, 80, 100, 120
Therefore,
LCM(16, 20) = 80
The least number of labels and envelopes you can buy so that there is one label on each envelope with none left over = 80 labels
Answer: (29.4, 32.6)
Step-by-step explanation:
From the question, we know that
Sample size (n) = 27
Sample mean (x) = $31
Sample standard deviation (s) = $3
We are to construct a 99% confidence interval interval for average amount spent on gift.
The formulae for constructing a 99% confidence interval for population mean is given as
u = x + tα/2 × s/√n...... For upper limit
u = x - tα/2 × s/√n...... For lower limit
tα/2 is the critical value for a 2 tailed test. This value of gotten from a t distribution table by checking the degree of freedom ( 27 - 1 = 26) against the level of significance ( 100% - 99% = 1%).
Hence tα/2 = 2.779
Let us substitute our parameters and solve
For lower limit
u = 31 - 2.779 × 3/√27
u = 31 - 2.779 ( 0.5773)
u = 31 - 1.6045
u = 29.4
For upper limit
u = 31 + 2.779 × 3/√27
u = 31 + 2.779 ( 0.5773)
u = 31 + 1.6045
u = 32.6
Hence the 99% confidence interval for population mean is given as 29.4, 32.6
Obtaining thevslope you get 6/5. so
9=-24/5 +n
=
y=6/5x + 21/5
