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4 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Mathematics

1 answer:

dimulka [17.4K]4 years ago

6 0

Answer:

the absolute value inequality in the form |x-b|c that has the solution set x≤−9 or x≥−5. lol jk

Step-by-step explanation:

|x−b|=c

Since we need three conditions that need to be met, we will opt for presenting three different expressions as a solution.

Case 1

One solution: x=−9

One expression that satisfies this condition is

(c = 0, b = -9 )

|x + 9|=0

|-9 + 9|=0

Case 2

All numbers such that x≤5

The solutions that satisfy this case can be found in the attached picture below, (they were obtained with a mathematical solver.)

Case 3

All numbers such that x≤-14

i pretty sure this is it.

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Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.

denis23 [38]

Answer:

$\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

$\text{Csc}\theta=-\frac{\sqrt{73}}{3}$

$\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = $\sqrt{x^{2}+y^{2}}$

R = $\sqrt{8^{2}+(-3)^2}$

= $\sqrt{64+9}$

= $\sqrt{73}$

Therefore, Cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

Sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }$

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Cscθ = $\frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}$

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4 years ago

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Step-by-step explanation:

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