Answer what? This question? Oh, I'm answering it right now. Did you have another question out? Well, I can't see it.
To find the zeros of this equation you need to first set it equal to zero
2x2 + 16x - 9 = 0
But since you can't FOIL this equation you need to move the non-variable number over
2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
2x +16 = 9
2x = -7
x = -7/2
So your zeros would be at x = 9, and -7/2
Answer:
Step-by-step explanation:
we have
we know that
substitute
Factor 2
![2[(2)x+(7)]](https://tex.z-dn.net/?f=2%5B%282%29x%2B%287%29%5D)
Answer:
The answer is 1.35 answer (1). You can graph both equations to give you the answer.
Step-by-step explanation:
Graph the equations and see where they intersect.
1 tenth if you are talking about the decimal
