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Komok [63]
3 years ago
13

Evaluate the summation of 2 times negative 2 to the n minus 1 power, from n equals 1 to 7..

Mathematics
2 answers:
sukhopar [10]3 years ago
6 0
Thank you for posting your question here at brainly. Feel free to ask more questions.  

<span>The best and most correct answer among the choices provided by the question is 86.</span><span>       
    </span><span>
<span>Hope my answer would be a great help for you.</span></span>
Mashutka [201]3 years ago
6 0

Answer:

(D) 86

Step-by-step explanation:

According to the question, the equation will be= \sum_{n=1}^{7}2(-2)^{n-1}.

Now,substituting the values of n from 1 to 7 in the above equation, we have

\sum_{n=1}^{7}2(-2)^{n-1} = 2(-2)^{0} + 2(-2)^{1}+ 2(-2)^{2}+ 2(-2)^{3} + 2(-2)^{4}+ 2(-2)^{5}+ 2(-2)^{6}

=2-4+8-16+32-64+128

=170-84

=86

Hence, the correct answer will be equal to 86.


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