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shepuryov [24]
2 years ago
13

There are 219 people at the science camp. 112 people are enrolled in the chemistry class, and 45 people are enrolled in the phys

ics class. How many students are enrolled in both classes if 79 students are not enrolled in either of them?
Mathematics
1 answer:
eimsori [14]2 years ago
6 0

Answer:

The correct answer is - 17.

Step-by-step explanation:

Given:

total students = 219

in chemistry = 112

in physics = 45

not enrolled in either of these = 79

solution:

The number of students in both classes can be calculated by

P ( A or B) = P (A) + P (B) - P (A and B)

then putting and solving the given vaues in formula

=> (219-79) = 112+45-x

=> 140 = 157 -x

=> 17 = x

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If (8^9)p = 8^16 what's the value of p?
monitta

Answer:

p  = {8}^{7}

Step-by-step explanation:

(8^9)p = 8^{16 } \\  \\ p =  \frac{8^{16 } }{8^{9 } }  \\  \\  p =  {8}^{16 - 9}  \\  \\  \huge \red{ \boxed{p  = {8}^{7} }}

8 0
2 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

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</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
When purchased, the height of a Japanese maple sapling is 14 inches. The tree is expected to grow 2.5 inches each month. Which f
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Answer:

Step-by-step explanation:

The initial height of a Japanese maple sapling is 14 inches.

The tree is expected to grow 2.5 inches each month. This increase in height is linear, thus it is in arithmetic progression.

The expression for arithmetic progression is

Tn = a + (n-1)d

Where a = the first term of the series

d = common difference

Tn is the nth term of the series

n = the number of terms.

From the information given

a = 14 inches because it is the initial height of the tree

d = 2.5 because it is the difference in height between 2 consecutive months

n = m( number of months)

Tn = f(m)

function models the relationship between the height of the tree f(m) and the number of m months of growth will be

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6 0
2 years ago
If AB is 12, what is the length of A'B'?
lukranit [14]

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8 months ago
What is the result of subtracting the second equation from the first?
gtnhenbr [62]
This is the answer with explanation

4 0
2 years ago
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