Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission, 
million ponds/day
Standard deviation, 
million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:
= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:
P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
So the actually surface area can be split up by dif parts....meaning
2 side is 2.7*3.2*2 = 17.28
2 side is 3.2*2.1*2 = 13.44
2 sides is 2.1*2.7*2= 11.34
then u add up the areas = 42.06ft^2
then u look for what is the clossest...and that is 42gt^2
Radius = diameter x 0.5
0.5x0.5 = 0.25meter
0.25 meter x 100 cm (100cm in one meter) = 25cm
also for future reference circumference = pie x r squared.
(k - 1)(k - 4)
Use FOIL to solve this.
First
k * k
Outer
k * -4
Inner
-1 * k
Last
-1 * -4
k^2 - 4k - 1k + 4
k^2 - 5k + 4 is the trinomial.
9x+3 y I’m in math hope that helps man
