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shusha [124]
3 years ago
5

"Bert has half as much money as Ernie. If Ernie loses $225 and Bert earns $675, Bert will have twice as much money as Ernie. How

much money do Bert and Ernie have before and after earning money
Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer: Ernie has $750 and Bert has \dfrac{750}{2}=\$375

Step-by-step explanation:

Let the amount that Ernie has be 'x'.

Let the amount that Bert has be \dfrac{x}{2}

Amount lost by Ernie = $225

Amount gained by Bert = $675

According to question, we get that

2(x-225)=\dfrac{x}{2}+675\\\\2x-450=\dfrac{x}{2}+675\\\\2x-\dfrac{x}{2}=675+450\\\\\dfrac{4x-x}{2}=1125\\\\\dfrac{3x}{2}=1125\\\\x=\dfrac{1125\times 2}{3}\\\\x=\$750

Hence, Ernie has $750 and Bert has \dfrac{750}{2}=\$375

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The area of a 2D form is the amount of space within its perimeter. The area of the garden is 72 feet² and the perimeter of the garden is 36 feet.

<h3>What is an area?</h3>

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

The diagram for the given garden is given below.

1.) The area of the garden is,

The area of the garden = Area of rectangle + Area of triangle

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2.) The perimeter of the garden is,

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Hence, the area of the garden is 72 feet² and the perimeter of the garden is 36 feet.

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Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
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Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

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if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

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