2 years ago

What are the solutions of -1 <=x-3<4? help asap

Mathematics

1 answer:

viva [34]2 years ago

4 0

I think the answer is -1=x-3<4

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Multiply (x-1)(x³+4x²+4x-1) and combine like terms. Explain how you reached your answer.

Hitman42 [59]

Answer:

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Step-by-step explanation:

To multiply this we are going to <u>multiply each term of the binomial by each term of the polynomial.</u>

$(x-1)(x^{3}+4x^{2} +4x-1)\\=x^4+4x^3+4x^2-x -x^3-4x^2-4x+1$

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$x^4+4x^3+4x^2-x -x^3-4x^2-4x+1 = x^4 +(4x^3-x^3)+(4x^2-4x^2)+(-x-4x)+1\\=x^4+3x^3-5x+1$

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3 years ago

Y= -3x^2-24x-46 write in vertex form

mario62 [17]

ANSWER

$y= -3{(x + 4)}^{2} + 2$

EXPLANATION

The given function is:

$y= -3x^2-24x-46$

Factor -3 for the first 2 terms.

$y= -3(x^2 + 8x)-46$

We add and subtract the square of the coefficient of x.

$y= -3(x^2 + 8x + {(4)}^{2} ) - - 3( {4)}^{2} -46$

Factor the perfect square trinomial.

$y= -3 {(x + 4)}^{2} ) + 48 -46$

The vertex form is:

$y= -3{(x + 4)}^{2} + 2$

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3 years ago

What are the solutions of -1 <=x-3<4? help asap ​

What are the solutions of -1 <=x-3<4? help asap