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Inessa [10]
3 years ago
10

During a race, a runner’s time was 4 seconds at the 36-meter mark and 6 seconds at the 57-meter mark. What was the runner’s aver

age speed, in meters per second, for the time interval between 4 seconds and 6 seconds? (A) 2.1 (B) 9.0 (C ) 9.3 (D)9.5 (E) 10.5
i need help ASAP ):
Mathematics
2 answers:
KIM [24]3 years ago
8 0

Answer:

The average speed of runner is given by option d) 10.5 meters per second.

Step-by-step explanation:

We are given the following information in the question:

A runner’s time was 4 seconds at the 36-meter mark.

A runner’s time was 6 seconds at the 57-meter mark.

Formula:

\text{Average speed} = \displaystyle\frac{y_2-y_1}{x_2-x_1}\\\\\text{where}, y_2, y_1 \text{are the distances at time} x_2, x_1 \text{respectively.}

Putting the given values in the question, we have:

\text{Average speed} = \displaystyle\frac{57-36}{6-4} = \frac{21}{2} = 10.5\text{ meter per second}

Hence, the average speed of runner is given by option d) 10.5 meters per second.

Arturiano [62]3 years ago
6 0

Answer:

E

Step-by-step explanation:

57 - 36 =  21              6 - 4 = 2 seconds

21 ÷ 2 = 10.5

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A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve
max2010maxim [7]

<u>Answer</u>:

The velocity of the tennis racket after the collision 14.966 m/s.

<u>Step-by-step explanation:</u>

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

So, the total kinetic energy before collision = the total kinetic energy after collision.

For the given problem let the following:

m₁ = mass of tennis racket = 0.311 kg

m₂ = mass of the ball = 0.057 kg

u₁ = velocity of tennis racket before collision = 30.3 m/s

u₂ = velocity of the ball before collision = -19.2 m/s

v₁ = velocity of tennis racket after collision

v₂ = velocity of the ball after collision

Right ⇒east  (+) , Left⇒ west (-)

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

  = ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)

  = 14.966 m/s.

So, the velocity of the tennis racket after the collision 14.966 m/s.

5 0
3 years ago
Factor Completely<br><br> -m^3-2m^2-16m-32
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Answer:

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Step-by-step explanation:

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tatiyna

Answer:

2\sqrt{8}

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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