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Mashcka [7]
3 years ago
5

STOCK MARKET During a 5-day

Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

Decrease = 13 points per day

Step-by-step explanation:

Since the market <em>decreased by 65</em><em> </em><em>in a week [week is 5 days]</em>, we need to find average daily decrease!

So we simply divide 65 by 5 to get the daily average.

65/5 = 13

Hence, average daily change in the market for the week is 13 points

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3 years ago
What is the distance between the following points?<br> WILL GIVE BRAINLIEST
frutty [35]

Answer:

D.√85

Step-by-step explanation:

We can find the distance between two points using the distance between two points formula

Distance between two points formula:

d = √(x2 - x1)² + (y2 - y1)²

Where the x and y values are derived from the given points

We are given the two points (-2,7) and (7,9)

Using these points let's define the variables ( variables are x1, x2, y1, and y2)

Remember points are written as follows (x,y)

The x value of the first point is -2 so x1 = -2

The x value of the second point is 7 so x2 = 7

The y value of the first point is 7 so y1 = 7

The y value of the second point is 9 so y2 = 9

Now that we have defined each variable let's find the distance between the two points

We can do this by substituting the values into the formula

Formula: d = √(x2 - x1)² + (y2 - y1)²

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d = √(7 - (-2))² + (9 - 7)²

Evaluation:

The two negative signs cancel out on 7-(-2) and it changes to +7

d = √ (7+2)² + (9-7)²

Add 7+2 and subtract 9 and 7

d = √ (9)² + (2)²

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We then have d = √ 81 + 4

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Check the picture below.

so we know S is the midpoint of PQ, and T is the midpoint of QR, thus

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&P&(~ -9 &,& 7~) &#10;%  (c,d)&#10;&Q&(~ -3 &,& 7~)&#10;\end{array}\quad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;S=\left( \cfrac{-3-9}{2}~,~\cfrac{7+7}{2} \right)\implies S=(-6,7)\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&Q&(~ -3 &,& 7~) &#10;%  (c,d)&#10;&R&(~ -3 &,& 1~)&#10;\end{array}&#10;\\\\\\&#10;T=\left(\cfrac{-3-3}{2}~,~\cfrac{1+7}{2}  \right)\implies T=(-3,4)

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\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&S&(~ -6 &,& 7~) &#10;%  (c,d)&#10;&T&(~ -3 &,& 4~)&#10;\end{array}\\\\\\ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;ST=\sqrt{[-3-(-6)]^2+[4-7]^2}\implies ST=\sqrt{(-3+6)^2+(4-7)^2}&#10;\\\\\\&#10;ST=\sqrt{3^2+(-3)^2}\implies ST=\sqrt{18}\implies ST=\sqrt{9\cdot 2}&#10;\\\\\\&#10;ST=\sqrt{3^2\cdot 2}\implies ST=3\sqrt{2}

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