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Mashcka [7]
3 years ago
5

STOCK MARKET During a 5-day

Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

Decrease = 13 points per day

Step-by-step explanation:

Since the market <em>decreased by 65</em><em> </em><em>in a week [week is 5 days]</em>, we need to find average daily decrease!

So we simply divide 65 by 5 to get the daily average.

65/5 = 13

Hence, average daily change in the market for the week is 13 points

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100 POINTS!!! Please solve this question step by step and explain each step for 100 points.
djverab [1.8K]

2\dfrac 29 = -\dfrac 45  m \\\\\implies 2+ \dfrac 29 =- \dfrac 45 m \\\\\implies \dfrac{20}9 = -\dfrac 45 m \\\\\implies 5(20) = (-4m)9\\\\\implies 100 = -36m\\\\\implies m = -\dfrac{100}{36} \\\\\implies m =  -\dfrac{25}9\\\\\implies m=-2\dfrac 79

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3 years ago
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Write 24 as a prime factors what is the answer
djverab [1.8K]
Write a number as prime factors means to write the number as a product of numbers, all of which are prime. We start by checking whether the number is divisible by prime numbers, starting from the smallest prime number,2.

let's divide 24 into its factors.

first, it's even, so it must divide by 2

24=2*12

12 is also even, so it must divide by 2:


24=2*12=2*2*6

6 is also even, so it must divide by 2:


24=2*12=2*2*6=2*2*2*3

3 is not even, but it's a prime number.

so the solution is
2*2*2*3



7 0
3 years ago
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Lines L and M are parallel lines cut by the transversals line t. which angle is congruent to angle 5
Stells [14]

Answer:

When two lines are cut by a transversal, the pairs of angles on one side of the transversal and inside the two lines are called the consecutive interior angles . If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary

Step-by-step explanation:

8 0
3 years ago
Approximate area under the curve f(x) =-x^2+2x+4 from x=0 to x=3 by using summation notation with six rectangles and use the the
bekas [8.4K]

Answer:

Summation notation:

\frac{1}{2}\sum_{k=1}^6f((.5k))

or after using your function part:

\frac{1}{2}\sum_{k=1}^6(-(.5k)^2+2(.5k)+4)

After evaluating you get 11.125 square units.

Step-by-step explanation:

The width of each rectangle is the same so we want to take the distance from x=0 to x=3 and divide by 6 since we want 6 equal base lengths for our rectangles.

The distance between x=0 and x=3 is (3-0)=3.

We want to divide that length of 3 units by 6 which gives a length of a half per each base length.

We are doing right endpoint value so I'm going to stat at x=3. The first rectangle will be drawn to the height of f(3).

The next right endpoint is x=3-1/2=5/2=2.5, and the second rectangle will have a height of f(2.5).

The next will be at x=2.5-.5=2, and the third rectangle will have  a height of f(2).

The fourth rectangle will have a height of f(2-.5)=f(1.5).

The fifth one will have a height of f(1.5-.5)=f(1).

The last one because it is the sixth one will have a height of f(1-.5)=f(.5).

So to find the area of a rectangle you do base*time.

So we just need to evaluate:

\frac{1}{2}f(3)+\frac{1}{2}f(2.5)+\frac{1}{2}f(2)+\frac{1}{2}f(1.5)+\frac{1}{2}f(1)+\frac{1}{2}f(.5)

or by factoring out the 1/2 part:

\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))

To find f(3) replace x in -x^2+2x+4 with 3:

-3^2+2(3)+4

-9+6+4

1

To find f(2.5) replace x in -x^2+2x+4 with 2.5:

-2.5^2+2(2.5)+4

-6.25+5+4

2.75

To find f(2) replace x in -x^2+2x+4 with 2:

-2^2+2(2)+4

-4+4+4

4

To find (1.5) replace x in -x^2+2x+4 with 1.5:

-1.5^2+2(1.5)+4

-2.25+3+4

4.75

To find f(1) replace x in -x^2+2x+4 with 1:

-1^2+2(1)+4

-1+2+4

5

To find f(.5) replace x in -x^2+2x+4 with .5:

-.5^2+2(.5)+4

-.25+1+4

4.75

Now let's add those heights.  After we obtain this sum we multiply by 1/2 and we have our approximate area:

\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))

\frac{1}{2}(1+2.75+4+4.75+5+4.75)

\frac{1}{2}(22.25)

11.125

Okay now if you wanted the summation notation for:

\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))

is it

\frac{1}{2}\sum_{k=1}^{6}(f(.5+.5(k-1)))

or after simplifying a bit:

\frac{1}{2}\sum_{k=1}^6 f((.5+.5k-.5))

\frac{1}{2}\sum_{k=1}^6f((.5k))

If you are wondering how I obtain the .5+.5(k-1):

I realize that 3,2.5,2,1.5,1,.5 is an arithmetic sequence with first term .5 if you the sequence from right to left (instead of left to right) and it is going up by .5 (reading from right to left.)

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3 years ago
Area of a 12 ft circle
Mnenie [13.5K]
113.10 feet, 16,286 square inches, 12.566 square yards, 10.507 square meters, 105,071 square centimeters
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