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aleksandr82 [10.1K]
3 years ago
12

Which of the following is the equation of a circle whose center is at the origin and whose diameter has end (-1,2) and (1,-2)

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

x² + y² = 5

Step-by-step explanation:

The circle with center (h, k) and radius r has equation ...

... (x -h)² + (y -k)² = r²

You can find r² using the Pythagorean theorem or the distance formula, or you can simply calculate what it needs to be to make one or the other of the points lie on the circle.

For (h, k) = (0, 0), the equation is ...

... (x -0)² + (y -0)² = r²

Using (-1, 2) for (x, y), we can find r² as ...

... (-1 -0)² + (2 -0)² = r² = 1 + 4 = 5

Then the circle equation is ...

... x² + y² = 5

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Jake has decided to invest in three business ventures. The total cost of investing in all three ventures is $15,000. The combine
Arte-miy333 [17]
X = first venture, y = second venture, z = third venture

x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....

x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000

x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000

2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000

x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000

first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
7 0
3 years ago
Read 2 more answers
I Need This ASAP will Give Brainly Whoever Is First.
Brums [2.3K]

Answer:

y intercept = (0, 3/2)

(The last one I think)

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5 0
3 years ago
"Raju's father age is 5 years more than three times of Raju's age. Raju's father age is 50 years."​
Lana71 [14]

Let rajus age be x

  • His father=3x+5

ATQ

\\ \bull\tt\longmapsto 3x+5=50

\\ \bull\tt\longmapsto 3x=50-5

\\ \bull\tt\longmapsto 3x=45

\\ \bull\tt\longmapsto x=\dfrac{45}{3}

\\ \bull\tt\longmapsto x=15

8 0
2 years ago
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2x^3+5x^2+6x+152x 3 +5x 2 +6x+15
Dmitrij [34]

ANSWER = 154^3+10^2+12+15

5 0
2 years ago
Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
3 years ago
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