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3 years ago

How is (+6) - (-11) different from (-6) - (+11)? Explain.

Mathematics

1 answer:

eimsori [14]3 years ago

4 0

Answer: One is a positive and one is Negative (+6) - (-11) = 17 and (-6) - (+11) = -17

Step-by-step explanation:

you can use the keep, change, change method

1.) (+6) - (-11)

Keep change change

2.) (+6) + 11 = 17

1.) (-6) - (+11)

keep change change

2.) (-6) + (-11) = -17

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Find the number, 112/ 100 of it is 56

Alinara [238K]

First let that number be y.
List the equation by the given info.
y x 112/100 = 56
Shift y to the other side by turning it to ÷y.
112/100 = 56/y
Use cross method,
100 x 56 = 112y
5600 = 112y
y = 50
Therefore that number is 50

6 0

3 years ago

What is 3x+8 if x=8

Mazyrski [523]

Answer:

y=32

Step-by-step explanation:

y=3(8)+8

y=24+8

24+8=32

y=32

4 0

3 years ago

Read 2 more answers

The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

Find the distance AB

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

Find the distance BC

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

Find the distance CD

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

Find the distance DE

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

Find the distance AE

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

6 0

3 years ago

Solve the system of equations y=-3/2x+9 2x+2y=16

ozzi

Answer:

x=2 and y=6

Step-by-step explanation:

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3 years ago

A time in history was called the Stone Age, Why was it called this?

mestny [16]

Answer:

HEY!

<h2>A time in history was called stone age because they were uneducated and they use to hunt animals with stones and so on.... And they even used to eat animals without frying...So, the people of stone age were totally uneducated but they were so creative more than us..</h2>

<h3>Hope it helps you!</h3><h3>Wish you luck......</h3>

8 0

3 years ago