G = {(5, 3), (2, 3), (6, 4)} Is G-1 a function and why?
1 answer:
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For this case we have the following difference equation:
Applying separable variables we have:
Integrating both sides we have:
applying exponential to both sides:
For y (1) = 1 we have:
Thus, the particular solution is:
Whose domain is all real.
Answer:
y = 0.2 * exp ((3/2) x ^ 2)
Domain: all real numbers
Applying separable variables we have:
Integrating both sides we have:
applying exponential to both sides:
For y (1) = 1 we have:
Thus, the particular solution is:
Whose domain is all real.
Answer:
y = 0.2 * exp ((3/2) x ^ 2)
Domain: all real numbers