Answer:
V=(πr^2 x h)/3
lets use π as 3.14 cause I dont know what pi u using
3.14 x 4^2 x 15 = 753.6/3 = 251.2
If you're using π as your pi, than just replace 3.14 by π on calculator
Hope that answers your question
Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer:
0
Step-by-step explanation:
Given that,
6m - 2n=0
=>6m=2n
=>n=3m [divide both side by 2]
& mn=12
Now,
216c - 8n³
= 216m³- 8(3m)³
=216m³- 8 .27m³
=216m³- 216m³
=0
Honestly photo math works for everything
Answer:
e 7 f 5 g is the square root of 74 I don't have a calculator on me sry
