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3 years ago

Please help me with this also good morning!

Mathematics

2 answers:

Doss [256]3 years ago

8 0

Answer:

Divide both sides by 6 :)

elena55 [62]3 years ago

5 0

Answer:

subtract 6 from both sides

Step-by-step explanation:

The basic technique to isolate a variable is to do something to both sides of the equation, such as add, subtract, multiply, or divide both sides of the equation by the same number.

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Which equation is equivalent to 2x + 6y = 12?

mixer [17]

Answer:

Option C, y = -1/3x + 2

Step-by-step explanation:

2x + 6y = 12

<u>Step 1: Solve for y</u>

2x + 6y - 2x = 12 - 2x

6y / 6 = (12 - 2x) / 6

y = 2 - 1/3x

Answer: Option C, y = -1/3x + 2

6 0

3 years ago

Read 2 more answers

I'm in a rush & I really need to solve these two problems:

Elenna [48]

1. 23.5 x 2.3 = 54.05
when you are multiplying decimals you have to line up the decimal point.
example:
23.5
2.3

2. 12.34 x 4.321 = 53.32114
once again you need to line up your decimals when multiplying two decimals.
example: however I had to add a zero to the number 12.34 so everything would line up correctly. I hope you understand that.
12.340
4.321

5 0

3 years ago

How do you this question (pre-cal)

Novay_Z [31]

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into $\csc^2( B )$

One way we can do that is through the following steps:

$\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\$

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

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