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3 years ago

What is the graph of y > x2-9.

Mathematics

1 answer:

Yakvenalex [24]3 years ago

8 0

Answer:

The 1st graph

Step-by-step explanation:

When you graph the equation in a graphing calc, you should be able to see that the graph most similar would be the 1st one.

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What is happening to this graph when the x-values are between - 1 and 1?

sp2606 [1]

Answer:

A. It’s decreasing

Step-by-step explanation:

Hey there!

Well on the graph at points -1 and 1 we can tell the line is going down,

meaning the line is decreasing.

Hope this helps :)

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3 years ago

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3 years ago

Reflect the triangle =(-1,-2), 4(1,1), V(4,- 3) across the line y = x

alekssr [168]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the line y = x

a point (x, y ) → (y, x ) , thus

(- 1, - 2 ) → (- 2, - 1 )

(1, 1 ) → (1, 1 )

(4, - 3 ) → (- 3, 4 )

5 0

3 years ago

What is the expression in radical form? (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

What is the graph of y > x2-9.​

What is the graph of y > x2-9.