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BlackZzzverrR [31]
3 years ago
15

Which value makes the equation 2x -4 = 16 true? *

Mathematics
2 answers:
professor190 [17]3 years ago
7 0
X = 10
Move the four to the right of the equal sign, and change it’s negative sign to a positive sign. Then, add 16 and 4. You will get 20. Then divide 2x and 20 by 2. You will get x = 10
Alinara [238K]3 years ago
4 0

Answer:

10 makes this equation true

Step-by-step explanation:

2x -4 = 16 /+4

2x= 20 /÷2

x= 10

Test

2(10) - 4 = 16

20 - 4 = 16 Correct

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36^ - 1/2 Wich is equivalent? A -18<br> B -6<br> C- 1/18<br> D- 1/6
STatiana [176]

Answer:

3rd

Step-by-step explanation:

3 0
3 years ago
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A three‐digit number satisfies the following conditions: The digits are consecutive whole numbers in increasing order; the sum o
IRINA_888 [86]
Answer: 123
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4 0
3 years ago
A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six
kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

V = Length \times Width \times Height \\\\

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

Width = 3 - 2x \\\\

The length of the shaded region is given by

Length = \frac{1}{2} (5 - 3x) \\\\

So, the volume of the box becomes,

V =  \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V =  \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V =  \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V =  \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

a = 18 \\\\b = -38 \\\\c = 15 \\\\

x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 +  19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\

Volume of the box at x= 1.59:

V =  \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\

Volume of the box at x= 0.53:

V =  \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0
3 years ago
Help ASAP!!!! Please someone help me
frosja888 [35]

Answer:

1 9/8

Step-by-step explanation:

Its a lot of explaining lol

8 0
3 years ago
Which of the fractions are equivalent to the fraction below?
yarga [219]
B. 2/5 is equal to 6/15
8 0
3 years ago
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