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3 years ago

9

The hart family drove 10 hours to their vacation spot. they drove an average of 48 miles each hour. how miles did they drive in

all

2 answers:

tankabanditka [31]3 years ago

8 0

Distance = Average speed * Time = 48*10 = 480 miles

So, they drove for 480 miles

tresset_1 [31]3 years ago

6 0

Answer: They drove 480 miles in all.

Step-by-step explanation:

The formula use to find distance :-

$\text{Distance}=\text{Time x Speed}$

Given : The hart family drove 10 hours to their vacation spot.

i.e. Time = 10 hours

They drove an average of 48 miles each hour.

i.e. Speed = 48 miles each hour

Then, $\text{Distance}=10\times48=480\text{ miles}$

Hence, they drove 480 miles in all.

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Kipish [7]

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17.98 square meters

Step-by-step explanation:

find the area of rectangle

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3 years ago

Kim solved the equation below by graphing a system of equations. log base 2 (3x-1) = log base 4 (x+8)

kompoz [17]

Answer:

solution is

$x=1.353,y=1.613$

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

5.349 round to the nearest tenth

soldi70 [24.7K]

5.4 because the 9 bumps it to 5.35.

And the 5 bumps it to 5.4.

6 0

2 years ago

Read 2 more answers

What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

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2 years ago