Answer:
<h2>A.Multiplication Property of Equality</h2>
Step-by-step explanation:
![\left\{\begin{array}{ccc}2x+2y=14\\-x+y=5&\text{\underline{multiply both sides by 2}}\end{array}\right\\\\\boxed{\underline{+\left\{\begin{array}{ccc}2x+2y=14\\-2x+2y=10\end{array}\right}}\qquad\text{add both sides of the equations}\\.\qquad\qquad4y=24\qquad\text{divide both sides by 4}\\.\qquad\qquad y=6\\\\\text{put the value of y to the second equation:}\\\\-x+6=5\qquad\text{subtract 6 from both sides}\\-x=-1\qquad\text{change the signs}\\x=1](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D2x%2B2y%3D14%5C%5C-x%2By%3D5%26%5Ctext%7B%5Cunderline%7Bmultiply%20both%20sides%20by%202%7D%7D%5Cend%7Barray%7D%5Cright%5C%5C%5C%5C%5Cboxed%7B%5Cunderline%7B%2B%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D2x%2B2y%3D14%5C%5C-2x%2B2y%3D10%5Cend%7Barray%7D%5Cright%7D%7D%5Cqquad%5Ctext%7Badd%20both%20sides%20of%20the%20equations%7D%5C%5C.%5Cqquad%5Cqquad4y%3D24%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%204%7D%5C%5C.%5Cqquad%5Cqquad%20y%3D6%5C%5C%5C%5C%5Ctext%7Bput%20the%20value%20of%20y%20to%20the%20second%20equation%3A%7D%5C%5C%5C%5C-x%2B6%3D5%5Cqquad%5Ctext%7Bsubtract%206%20from%20both%20sides%7D%5C%5C-x%3D-1%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5Cx%3D1)
Answer:
Test is cheating asking on brainly
Step-by-step explanation:
d = 53
![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n)
Answer:
<u>I'll give the choices by the number below:</u>
- 1. 45 miles. Taken from the table at day 0.
- 2. 39 miles. Given for Miguel.
- 3. Jose's. His goal has a greater value 45 > 39.
- 4. 5 miles a day. Change per day as per table.
- 5. 6.5 miles a day. Given.
- 6. Miguel's. Comparing 6.5 > 5
Answer:
Step-by-step explanation:
Can you rephrase the question.
Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)