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rewona [7]
3 years ago
9

If e^9xe^2xe^-8=e^x what is the value of x

Mathematics
1 answer:
Inessa [10]3 years ago
6 0

Answer:ur daaddy

Step-by-step explanation:

You might be interested in
WILL GIVE BRAINLY Find the perimeter of the figure below, in meters.
yan [13]

Answer:

147.6\:\mathrm

Step-by-step explanation:

The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.

Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:

9.8+9.8+11.7+9.8+21.5+21+11.7+9.8+31.3+11.2=\boxed{147.6\:\mathrm{m}}

Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.

3 0
3 years ago
What is the value of 4x to the third +4x if x is 4
weqwewe [10]
The correct answer of
4{x}^{2}  + 4x
if x=4 is 272.

to solve the equation if x equals 4, you must substitute the x of the 4.
4( {4}^{3} ) + 4(4)
then solve by order of operations.
solve what is inside the parentheses first
4(64) + 4(4)
then do the multiplication of the factors
256 + 16
then the final step, adding, to get the solution of 272
5 0
3 years ago
Claire is ordering trophies for her school. Company A charges $4.50 for each trophy and a one-time engraving fee of $26. Company
Ugo [173]

Answer:

my putyy

Step-by-step explanation:

ong its my putty hehehe

5 0
3 years ago
5√48-4√27-2√108+√147
irakobra [83]

Answer:

3\sqrt{3}

Step-by-step explanation:

8 0
3 years ago
From a thin piece of cardboard 30 in. by 30 in., square corners are cut out so that the sides can be folded up to make a box. Wh
Brilliant_brown [7]

Answer:

Dimensions 5in x 10in x 10in will yeild a box with a max. volume of  500 cubic inches

Step-by-step explanation:

Volume =  height x length x width

considering 'x' as the length of the square corners that has been cut out from the cardboard and also, that is height of the cardboard box.

square corners are cut out so that the sides can be folded up to make a box, cardboard sides would reduce by 2x

therefore,

V = x  (30-2x) (30-2x) ---> eq(1)

V=( 30x - 2x²) (30-2x)

V= 900x- 60x² - 60x² + 4x³

V=  4x³ - 120 x²+ 900x

Taking derivative w.r.t 'x'

dV/dx = 12x² - 240 x +900

dV/dx = 4 (3x² - 60x +225)

For maximum dV/dx, make it equal zero

dV/dx = 0

so,  4 (3x² - 60x +225)=0

3x² - 60x+225=0   (taking 3 common)

x² - 20x + 75 =0

Solving this quadratic equation

x² - 15x -5x + 75 =0

x(x-15) - 5(x-15) =0

Either (x-15)=0

x=15

Or x-5=0

x = 5

if we substitute x=15 in eq(1), volume becomes zero.

therefore, x cannot be 15

When x= 5

eq(1)=>V = 5  (30-2(5)) (30-2(5))

V= 5 (10) (10)

V= 500 cubic inches,

Therefore, Dimensions 5in x 10in x 10in will yeild a box with a max. volume of  500 cubic inches

7 0
3 years ago
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