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In-s [12.5K]
2 years ago
6

Triangle LMN and QRS are similar. Find x.

Mathematics
1 answer:
solong [7]2 years ago
5 0
<span>Line LM= x+5 and is proportional to line QR which equals 30. Line LN= 50 and is proportional to line QS which equals 75. 
</span>The answer is 11.3
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2 years ago
Use the Quadratic formula to find all real zeros of the 2nd degree polynomial
schepotkina [342]

Answer:

  x ∈ {-5, -1}

Step-by-step explanation:

Here's the solution using the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-24\pm\sqrt{24^2-4\cdot 4\cdot 20}}{2\cdot 4}\\\\=\dfrac{-24\pm\sqrt{576-320}}{8}=\dfrac{-24\pm\sqrt{256}}{8}\\\\=\dfrac{-24\pm 16}{8}=-3\pm 2=\{-5,-1\}

The real zeros are -5 and -1.

_____

There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.

Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.

4 0
2 years ago
What is the mean of 45,50,47,52,53,45,51
Alina [70]

Answer:

Mean is 49

Step-by-step explanation:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count. Please give me the brainliest answer.

Hope this helped :D have a good day!!!

8 0
3 years ago
The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

r=10/2=5\ units ---> the radius is half the diameter

A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

A=25\pi-16\pi+9\pi-4\pi+\pi

A=15\pi\ units^2

7 0
3 years ago
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