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sergeinik [125]
3 years ago
15

. .06 cm = ________ mm

Mathematics
2 answers:
Alborosie3 years ago
5 0

Answer:

  • 0.6

Step-by-step explanation:

Hope it helps! :)

german3 years ago
5 0

Answer:

0.6

Step-by-step explanation:

hope this helps

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Mr Floyd is laying grass squares in his backyard. He will cover the entire yard except for the vegetable garden. How many square
Alenkasestr [34]

Here we can first find the area of yard and then subtract the area of vegetable garden to get the required area.

The formula to find area is given by:

A = l* w

Now we find area of yard:

length is 25 ft and width is 15 ft.

A = 25 * 15

Area of yard = 375 ft²

Area of vegetable garden:

length = 8ft and width =8ft

So the vegetable garden is a square.

Area = 8*8

Area of vegetable garden =64 ft²

Area of backyard to be laid with grass = Area of yard-Area of vegetable garden

Area required = 375 -64 = 311 ft²

Answer : The area of backyard in which grass is to be laid is 311 square feet.

3 0
3 years ago
Read 2 more answers
Write the equation of a line in slope-intercept form that has a slope of -0.5 and passes through the point (-5, 1.5)
baherus [9]
Y = -1/5x + 0.5
The y intercept is 0.5
3 0
3 years ago
Subtracing 3x2+4x-5 from 7x2-3x from this polynomial the difference is
kolezko [41]
7x^2-3x - (3x^2 +4x -5)  multiply negative one across the entire second term

7x^2 - 3x -3x^2 -4x +5

4x^2 -7x +5
4 0
3 years ago
Find area of a square garden having a length 45m ​
Oliga [24]

Answer:

A = 2025 ft^2

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

A = 45^2

A = 2025 ft^2

7 0
3 years ago
Read 2 more answers
Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

3 0
3 years ago
Read 2 more answers
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