The difference of mean for the given set of terms including the outlier and excluding the outlier is 1.01.
<h2>Mean</h2>
The arithmetic mean for a given set of numbers is defined as the central value for the given set of numbers.
Given that Sasha runs a 5k race. Her time in minutes is recorded in the table:
- Jan 39. 55
- Feb 40. 51
- Mar 41. 01
- Apr 37. 76
- May 35. 32
- June 33. 28
- July 34. 38
- Aug 36. 48
- Sept 39. 87
- Oct 50. 32
- Nov 40. 59
- Dec 41. 71.
The mean for the given set of terms can be calculated by the total sum of all the terms divided by the total number of terms.
Mean = 
Mean = 39.23
Thus the mean of the given set of terms is 39.23.
The outlier term in the given set of terms is 50.32. If we exclude this outlier term, then the mean will be given as below.
Mean = 
Mean = 38.22
The difference between the mean including the outlier and excluding the outlier is given below.
Difference = 39.23 - 39.22
Difference = 1.01
Hence we can conclude that the difference of mean for the given set of terms including the outlier and excluding the outlier is 1.01.
To know more about the mean, follow the link given below.
brainly.com/question/12513463.
where
is the cumulative distribution function of
. We have probability density given by
which yields the CDF
and so
Answer:
Step-by-step explanation:
Given points P(1, -1, 4), Q (4,2,1) vector equation of a line joining the points with position vectors r₀ and r₁ is:
r = (1 - t)r₀ + tr₁
where
t ∈ [0, 1]
and r₀ = P = (1, -1, 4)
r₁ = Q = (4, 2, 1)
r(t) = (1 - t) 
+ t
∴
The vector equation where t ∈ [0,1] is:
r(t) = (1+3t)i - (1+3t)j + (4 - 3t)k
The parametric equation is:
x(t) = 1 + 3t
y(t) = -1 + 3t
z(t) = 4 - 3t
(x(t), y(t), z(t) ) = ( 1 + 3t, -1 + 3t, 4 - 3t )
8 ^ (-2) = 1 / 64
<span>4 ^ (-3) = 1 / 64</span>
Consider that the three consecutive integers are:
least integer = n
middle integer = n + 1
greatest integer = n + 2
THe expression "three consecutive integers is 12 less than 4 times the middle integer" can be written as follow:
n + (n + 1) + (n + 2) = 4(n +1) - 12
In order to find the numbers, proceed as follow:
n + (n + 1) + (n + 2) = 4(n +1) - 12 cancel parenthesis
n + n + 1 + n + 2 = 4n + 4 - 12 simplify like terms
3n + 3 = 4n - 8 subtract 4n and 3 both sides
3n - 4n = - 8 - 3
-n = -11
n = 11
Hence, the three consecutive integers are:
n = 11
n + 1 = 12
n + 2 = 13
