Answer:
Binomial; \mu p=87.5, \sigma p=7.542
Step-by-step explanation:
- a distribution is said be a binomial distribution iff
- The probability of success of that event( let it be p) is same for every trial
- each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
- there are fixed number of trials (n)
- the trials are independent
- here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
- the probability of success(0.35) is same for every trial
(35/100=0.35 is the required p here)
[since, the formula for
]
[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}
- therefore, it is Binomial; \mu p=87.5, \sigma p=7.542
Answer:
See sample table below.
Step-by-step explanation:
The function is given as :
f(x) = 3ˣ
A table of values can be formed as ;
x <u>calculations</u> f(x)
-4 3⁻⁴ 0.0123
-3 3⁻³ 0.0370
-2 3⁻² 0.1111
-1 3⁻¹ 0.3333
0 3⁰ 1.000
1 3¹ 3.000
2 3² 9.000
3 3³ 27.00
4 3⁴ 81.00
Answer:
(-1,1) because -1 and 1 are not inclusive
Step-by-step explanation:
from x = -1 to x = 1, the y-value keeps decreasing from 4 to 2
there is another one, (3,5)
The partial peoduct is 301.
Answer:
a = -0.3575
Step-by-step explanation:
The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.
The points A and B are located where

This gives


Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

Thus the coordinates of B are:

Now this point B lies on the parabola, and therefore it must satisfy the equation 
Thus

Therefore

