Question

Factor. 9x^4−64y^2 HELPPPP PLEASE

Answer 1

Final result :

(3x2 + 8y) • (3x2 - 8y)


Also sub to Stariceie E

Answer 2

Answer:

Step-by-step explanation:

Factoring the difference of two squares is as follows:

$a^{2} - b^{2} = (a + b)(a - b)$

In the given problem, you know that $9x^{4}$ can be broken down to $3x^{2} * 3x^{2}$, and that $64y^{2}$ can be broken down to $8y * 8y$, so plugging those numbers into the above equation, we get the following:

$9x^{4} - 64y^{2}$

$(3x^{2} + 8y)(3x^{2} - 8y)$