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Brilliant_brown [7]
3 years ago
8

Last month a cafe had 3200 customers 600 of them ordered gluten-free meals

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer: 18.75%

Step-by-step explanation:

Here is the complete question:

Last month, a cafe had 3200 customers. 600 of them ordered gluten-free meals. What percentage of the customers ordered gluten-free meals?

To find the percentage of the customers who ordered gluten-free meals, we will divide the number of people who ordered glutton free meal by the total number of customers and then multiply by 100. This will be:

= 600/3200 × 100

= 0.1875 × 100

= 18.75%

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Terday. Priya successfully made 6 free throws. Today, she made 75% as
tatuchka [14]

Answer:

10

Step-by-step explanation:

Yesterday, Priya successfully made 6 free throws.

Today, she made 75% as many as yesterday.

We are asked to calculate the number of successful free throws that Priya made today.

So, the number will be 6 (1 + \frac{75}{100} ) = 10.5.

Since it is the number of successful free throws, so it will be 10 throws. ( Answer )  

4 0
3 years ago
3x-2+x+8=1/2(9x+7-x+5)
Elanso [62]

Answer:

Step-by-step explanation:

3 0
3 years ago
-6x+y=8<br> 5x+y=8 <br><br> using elimination method
asambeis [7]

Answer:

x=0, y=8. (0, 8).

Step-by-step explanation:

-6x+y=8

5x+y=8

-----------

-6x+y=8

-(5x+y)=-8

--------------

-6x+y=8

-5x-y=-8

-------------

-11x=0

x=0/-11

x=0

5(0)+y=8

0+y=8

y=8-0

y=8

7 0
3 years ago
Solve for x: 3 − (2x − 5) &lt; −4(x + 2)
Firdavs [7]

Answer:

A. x < -8 (first option)

Step-by-step explanation:

3 - (2x - 5) <  - 4(x + 2)

3 - 2x + 5 <  - 4x - 8

8 - 2x <  - 4x - 8

- 2x + 4x <  - 8 - 8

2x <  - 16

\boxed{\green{x <  - 8}}

6 0
3 years ago
Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0
Jlenok [28]
This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

4 0
3 years ago
Read 2 more answers
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