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ExtremeBDS [4]
3 years ago
7

Which graphThe Pythagorean theorem states that the sum of the squares of the legs of a right triangle is equal to the square of

the hypotenuse by the formula a2 + b2 = c2.
If a is a rational number and b is a rational number, why could c be an irrational number? represents the solution set of the compound inequality mc011-1.jpg?
Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0
Because even though 'a' and 'b' are rational, and their squares are
also rational, that doesn't guarantee that the sum of their squares
has a rational square root.

Examples:

1 and 2
Sum of squares = 5
√5 is irrational

2 and 3
Sum of squares = 13
√13 is irrational

4 and 5
Sum of squares is 41
√41 is irrational

'c' is rational only when 'a', 'b', and 'c' form a . . . . . wait for it . . . . .
a 'Pythagorean triple'.

Examples:

3 and 4
Sum of squares is 25
√25 = 5 is rational                yay

5 and 12
Sum of squares is 169
√169 = 13 is rational            yay
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6x - 3y = -6<br> y = 2x + 2
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Answer:

y=0, x=1

Step-by-step explanation:

6x-3y= -6 ...... equation 1

y =2x+2 ..... equation 2

subtract 2x from both sides

y-2x=2x-2x+2

y-2x=2

6x-3y= -6

y-2x=2

Rearrange

6x-3y= -6 ........x1

-2x +y=2............x3

6x-3y= -6

-6x +3y=2

0y=0

y=0

substitute y=0 in equation 1

6x-3xo= -6

6x= -6

x-6/6

x = -1

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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                   w = sin27*38/sin40

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