What is the exact area of a circle having the diameter of 6in A:9 pie B: 36pie C: 6 pi D: 3pie

nalin [4]

Answer:

290.5 square miles

Step-by-step explanation:

Consider splitting this figure into two mini rectangles and a triangle, each of given lengths;

$Dimensions of Rectangle 1 - Height ; 5 mi, Length ; 7 mi,\\Area of Rectangle 1 - Height * Length = 5 mi * 7 mi = 35 mi^2\\\\Dimensions of Rectangle 2 - Height ; 18 mi, Length ; 8 mi,\\Area of Rectangle 2 - Height * Length = 23 mi * 8 mi = 184 mi^2\\\\Dimensions of Mini Right Triangle - Height ; 11 mi, Base ; 8 + 5 = 13 mi,\\Area of Mini Right Triangle - 1 / 2 * Base * Height = 1 / 2 * 13 mi * 11 mi = 71.5 mi^2,\\\\Area of Figure = 35 mi^2 + 184 mi^2 + 71.5 mi^2 = 290.5 square miles$

Solution; 290.5 square miles

4 0

3 years ago

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Irina-Kira [14]

Answer:

The answer is x= -10

3 0

3 years ago

The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen

BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

$c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm$

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

$\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} = \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm$

$r = 8.9 \pm 0.2 cm$

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

$A=\pi r^{2}\\A=249 cm^{2}$

Then we calculate the error:

$\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}$

$A=249 \pm 11.2 cm^{2}$

Now we proceed to calculate the percent error:

$\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%$

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

$\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}$

Now we calculate the error for the radius:

$\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm$

Now we proceed with the error for the circumference:

$\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm$

5 0

3 years ago

Question 1 (Essay Worth 10 points)

Shalnov [3]

✿————✦————✿————✦————✿

The answer is: 2(k2−4k)(2c+5)

✿————✦————✿————✦————✿

Step:

* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.

* Factor out the common term 2c+5 by using the distributive property.

* Rewrite the complete factored expression.

✿————✦————✿————✦————✿

6 0

2 years ago

I really need help and this answered ASAP. thank you and sorry.

Semenov [28]

9514 1404 393

Answer:

$2.50

Step-by-step explanation:

The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.

Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.

The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.

(8n +4p) -4(3n +2p) = (16.00) -4(6.50)

-4n -4p = -10.00 . . . . . . . . . . . simplify

n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)

The total cost for one notebook and one pen is $2.50.

__

Additional comment

The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.

One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.

4 0

3 years ago

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