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3 years ago

Which is larger 143.0 millimeters or 143.0 decimeters?

1 answer:

6 0

1 millimeter = 10⁻³ m
1 decimeter = 10⁻¹ m
So,decimeters are larger units, and 143.0 decimeters > 143.0 millimeters .

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Andrew has already played 32 minutes on his video game today and wants to play an additional 15 minutes each of x games after sc

artcher [175]

Answer:

y = 15x+32

Step-by-step explanation:

Given

y to be the total minutes Andrew will play video games today

x is the total number of games played after school

If he wants to play an additional 15 minutes each of x games after school today, the total minutes he will use for the x games will be 15* x = (15x)minutes

We are told that he has initially spent 32minutes on video games. hence;

Total minutes Andrew used on games y = (15*x)+32

The required equation will be y = 15x+32

7 0

3 years ago

Could someone help me ASAP, thanks !!

Rashid [163]

Answer:

I think this is the right answer but last two signs are incorrect

Hope this will help

6 0

3 years ago

Read 2 more answers

Please help its inequalities 2x < 6

Katyanochek1 [597]

$x < 3$
hope it helps

4 0

4 years ago

Divide using LONG Division (m? + 2m - 15) + (m + 5)

user100 [1]

Answer:

I hope you got it and it helped you

7 0

3 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0

1 year ago