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3 years ago

13

Forty-eight pounds of sand are used to fill 12 bags. Miranda uses the five-step problem-solving plan. After completing the Solve

step, how many pounds of sand should she find each bag will hold? Enter you answer in the box.

2 answers:

Novosadov [1.4K]3 years ago

7 0

Each bag would hold 4 pounds of sand because 48 / 12 = 4

Alja [10]3 years ago

3 0

48 lbs / 12 bags

About 4 pounds of sand per bag

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marissa [1.9K]

B. b(x) = (50x) - 150

C. f(x) was moved down 150 units

I hope this helps!

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3 years ago

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA

professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

$A=45e^{-0.0045(t)}$

a) To find the initial amount of this substance

At t=0, we get

$A=45e^{-0.0045(0)}$ $A=45e^0$

We know that e^0=1 ( anything to the power zero is 1)

we get,

$A=45$

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

$\frac{45}{2}=45e^{-0.0045(t)}$

$\frac{1}{2}=e^{-0.0045(t)}$

Taking natural logarithm on both sides we get,

$\ln (\frac{1}{2})=-0.0045(t)^{}$ $(-1)\ln (\frac{1}{2})=0.0045(t)$ $\ln (\frac{1}{2})^{-1}=0.0045(t)$ $\ln (2)=0.0045(t)$ $0.6931=0.0045(t)$ $t=\frac{0.6931}{0.0045}$ $t=154.02$

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

$A=45e^{-0.0045(2500)}$ $A=45e^{-11.25}$ $A=45\times0.000013=0.000585$ $A=0.000585$

The amount of substance will be present around in 2500 years is 0.000585 grams

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1 year ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Slope intercept form is y=mx+b

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3 years ago

Read 2 more answers

Suppose Burger King has run a major advertising campaign in the hopes of increasing monthly sales. To investigate the effectiven

Alexxandr [17]

Answer:

The right answer is:

a.H0: μd = 0; H1: μd > 0

Step-by-step explanation:

The claim that want to be tested is that the sales were significantly increased after the commercial, indicanting that the advertisement campaign was effective.

This claim is usually expressed in the alternative hypothesis as it has to have enough evidence to prove that it is true.

Then, the alternative hypothesis H1 should state that the difference (sales after - sales before) is higher than 0.

The null hypothesis would state that the difference is not significantly different from 0, or, in other words, that the sales are the same before and after and that the variation is due to pure chance.

Then, the null hypothesis H0 would state that the difference is equal to 0.

The right answer is:

a.H0: μd = 0; H1: μd > 0

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3 years ago