Answer: The correct option is (D) SET 4.
Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.
To form a right-angled triangle, we must have the following relation:
<em>Perpendicular² + Base² = Hypotenuse².</em>
<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>
SET 1 : 14 cm, 5 cm, 6 cm.
We have
![5^2+6^2=25+36=61,\\\\14^2=196.](https://tex.z-dn.net/?f=5%5E2%2B6%5E2%3D25%2B36%3D61%2C%5C%5C%5C%5C14%5E2%3D196.)
Therefore,
<em>Perpendicular² + Base² ≠ Hypotenuse².</em>
So, this set will not form a right-angled triangle.
SET 2 : 8 in., 12 in., 20 in.
We have
![8^2+12^2=64+144=208,\\\\20^2=400.](https://tex.z-dn.net/?f=8%5E2%2B12%5E2%3D64%2B144%3D208%2C%5C%5C%5C%5C20%5E2%3D400.)
Therefore,
<em>Perpendicular² + Base² ≠ Hypotenuse².</em>
So, this set will not form a right-angled triangle.
SET 3 : 10 mm, 20 mm, 30 mm.
We have
![10^2+20^2=100+400=500,\\\\30^2=900.](https://tex.z-dn.net/?f=10%5E2%2B20%5E2%3D100%2B400%3D500%2C%5C%5C%5C%5C30%5E2%3D900.)
Therefore,
<em>Perpendicular² + Base² ≠ Hypotenuse².</em>
So, this set will not form a right-angled triangle.
SET 4 : 12 ft, 16 ft, 20 ft.
We have
![12^2+16^2=144+256=400,\\\\20^2=400.](https://tex.z-dn.net/?f=12%5E2%2B16%5E2%3D144%2B256%3D400%2C%5C%5C%5C%5C20%5E2%3D400.)
Therefore,
<em>Perpendicular² + Base² = Hypotenuse².</em>
So, this set will form a right-angled triangle.
Thus, the SET 4 will form a right-angles triangle.
Option (D) is correct.